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anonymous

  • one year ago

Help with equation/scenario

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  1. anonymous
    • one year ago
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    @Nnesha hey can you confirm my answer form ? I got like 3.989 so I'm going with that. I did it by hand so I just want someone to check.

  2. Nnesha
    • one year ago
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    x is an exponent ?

  3. Nnesha
    • one year ago
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    can you please explain or show ur work plz how did you get that answer ? :=)

  4. Nnesha
    • one year ago
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    what was ur first step ?

  5. Nnesha
    • one year ago
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    hey?? :(

  6. anonymous
    • one year ago
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    hey sorry afk again. this is what I did (30000=1.18^x * 15 30000=1.18^x * 500) I used scalar multiplying

  7. anonymous
    • one year ago
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    @Nnesha

  8. anonymous
    • one year ago
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    my book has a whole section on that in this lesson so I thought that was what I do but idk

  9. Nnesha
    • one year ago
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    i don't know why or how you separated de 15 and 5000\[\huge\rm 30000=15500(1.18)^x\] you need to get rid of the 15500 so you can take ln both sides

  10. Nnesha
    • one year ago
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    divide both sides by 15500 and then take natural log

  11. anonymous
    • one year ago
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    okay so 30000 / 15500 is 1.9354 and then just 1.18^x I think

  12. anonymous
    • one year ago
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    Sorry if I'm not doing this right. Really trying though

  13. Nnesha
    • one year ago
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    yes right \[\huge\rm 1.935=(1.18)^x\] now take natural log both sides

  14. anonymous
    • one year ago
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    isn't natural log just log10? I think someone told me that

  15. Nnesha
    • one year ago
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    ln is basically same as log same rules applies for both but ln has base e and and log_!0

  16. Nnesha
    • one year ago
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    log_10

  17. anonymous
    • one year ago
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    I'm sorry can you show me how to set it up?

  18. Nnesha
    • one year ago
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    sure btw you can take ln or log you will get the same answer if you take `ln` \[\huge\rm \color{ReD}{ln} 1.935=\color{red}{ln}(1.18)^x\] or `log` \[\huge\rm \color{ReD}{log} 1.935=\color{red}{log }(1.18)^x\]

  19. Nnesha
    • one year ago
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    now apply the power rule \[\large\rm log_b x^y = y \log_b x\]

  20. Nnesha
    • one year ago
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    move the x exponent at front of log or ln

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