Destinyyyy
  • Destinyyyy
Help with 5 problems...
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Destinyyyy
  • Destinyyyy
2 [7- 3/2x] +5=21 [] are absolute value lines
Destinyyyy
  • Destinyyyy
7- 3/2x =8
Destinyyyy
  • Destinyyyy
Not sure what to do next

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Destinyyyy
  • Destinyyyy
@Nnesha @freckles @Vocaloid
Vocaloid
  • Vocaloid
you're on the right track, but when we have absolute value signs, we must consider the positive and negative solutions to the equation so, going by what you have so far, we have: | 7 - 3/2x | = 8, where | | are the absolute value signs, with me so far?
Destinyyyy
  • Destinyyyy
Yes
Vocaloid
  • Vocaloid
So, going from there, we need to write two different equations 7 - 3/2x = 8 and 7 - 3/2x = -8
Vocaloid
  • Vocaloid
then we solve each one separately so, let's tackle the first one 7 - 3/2x = 8 first, subtract 7 from both sides and tell me what you get
Destinyyyy
  • Destinyyyy
- 3/2x= 1
Vocaloid
  • Vocaloid
yup, now we divide both sides by (-3/2)
Destinyyyy
  • Destinyyyy
um -2/3
Vocaloid
  • Vocaloid
yup, so x = -2/3 now, we're only halfway done, there's another value of x that works for the equation. now we solve 7 - (3/2)x = -8 using the same process as before. start by subtracting 7 from both sides
Destinyyyy
  • Destinyyyy
x=10
Vocaloid
  • Vocaloid
yup, so x = 10 and x = -2/3 are your two solutions, good work ready for the next one?
Destinyyyy
  • Destinyyyy
Yes thank you
Destinyyyy
  • Destinyyyy
Solve. [x+8] +9=7 same as the one before
Destinyyyy
  • Destinyyyy
I got x=-10
Vocaloid
  • Vocaloid
ah, not quite, there's an important rule to remember when it comes to absolute values. the absolute value of a mathematical expression cannot be negative as an example, if we have |x| = a, then a must be a positive number in order to have a solution so, looking at our problem, we first subtract 9 from each side to get |x + 8| = -2 the absolute value of any quantity must be positive, so this has no solution
Destinyyyy
  • Destinyyyy
Okay
Vocaloid
  • Vocaloid
does that make sense? are you ready to move to the next one?
Destinyyyy
  • Destinyyyy
Yes it does. I thought it was but wanted to make sure.. Solve using appropriate substitution. (x^2 -6x)^2 -11(x^2 -6x) -30=0
Destinyyyy
  • Destinyyyy
I got 3+- square root 14 and 3+- square root 15 But its wrong...
Vocaloid
  • Vocaloid
huh, this is a tricky one, hold on a moment
Destinyyyy
  • Destinyyyy
Okay
Vocaloid
  • Vocaloid
well, I'm not sure if this is the right approach but...I'm guessing it wants us to substitute a variable for x^2 -6x so, if we let a = x^2 -6x, then our equation becomes a^2 - 11a - 30 after we apply the quadratic formula we get |dw:1440800955390:dw|
Destinyyyy
  • Destinyyyy
I factored (w-5)(w-6)
Vocaloid
  • Vocaloid
I'm not really sure if my thinking is correct and that factoring doesn't work, that would only work for positive 30, not -30 (w-5)(w-6) = w^2 - 11w + 30
Destinyyyy
  • Destinyyyy
Oops
Vocaloid
  • Vocaloid
ah, I wish I could be of more help on this one :( I feel like I'm missing an obvious trick here @welshfella @SithsAndGiggles
Destinyyyy
  • Destinyyyy
Its okay really. Your being super helpful :)
anonymous
  • anonymous
Given that \(a^2 - 11a - 30=0\) yields roots \(a=\dfrac{11\pm\sqrt{241}}{2}\), you can find the roots to \(x^2-x-a=0\) by applying the QF again.
anonymous
  • anonymous
typo: \(x^2-\color{red}6x-a=0\)
Destinyyyy
  • Destinyyyy
Um okay..
dinamix
  • dinamix
w(1) = 5 or w(2) = 6
Destinyyyy
  • Destinyyyy
So... 1+- square root 5 over 2
dinamix
  • dinamix
2 solution w(1) = 5 and w(2) = 6
dinamix
  • dinamix
@Destinyyyy
Destinyyyy
  • Destinyyyy
Okay but how did you get to that?? Id like to know how to solve this
dinamix
  • dinamix
\[\Delta = 1\]
dinamix
  • dinamix
u should find that
Destinyyyy
  • Destinyyyy
The triangle is square root correct?
Destinyyyy
  • Destinyyyy
What?? O.o
dinamix
  • dinamix
\[w =\frac{ 11 \pm \sqrt{121-120} }{ 2} \]
Destinyyyy
  • Destinyyyy
Yes I have that
Destinyyyy
  • Destinyyyy
Except I have a positive 120
Destinyyyy
  • Destinyyyy
121+120=241
Destinyyyy
  • Destinyyyy
Now what?
dinamix
  • dinamix
u have mistake
Destinyyyy
  • Destinyyyy
Where?
dinamix
  • dinamix
b^2-4ac = \[(-11^2) - 4*1*30\]
dinamix
  • dinamix
u looking for this w^2-11w+30 @Destinyyyy
Destinyyyy
  • Destinyyyy
its a negative 30 not positive...
Destinyyyy
  • Destinyyyy
The original problem contains a -30
dinamix
  • dinamix
what is your problem could u tell me what is equation
dinamix
  • dinamix
plz
Destinyyyy
  • Destinyyyy
Solve using appropriate substitution. (x^2 -6x)^2 -11(x^2 -6x) -30=0
Destinyyyy
  • Destinyyyy
w^2 -11w -30=0 w^2--> (x^2-6x)^2 w--> x^2 -6x
dinamix
  • dinamix
are u sure its -30 ? cuz like that we dont have good numbers
Destinyyyy
  • Destinyyyy
Its actually -80 ... I miss read. So sorry
Destinyyyy
  • Destinyyyy
Everything else is correct
dinamix
  • dinamix
so give me right equation without mistakes
dinamix
  • dinamix
ok
Destinyyyy
  • Destinyyyy
Solve using appropriate substitution. (x^2 -6x)^2 -11(x^2 -6x) -80=0 I can screenshot it if you want
dinamix
  • dinamix
ok so w(1) = 5 and w(2) = 16
Destinyyyy
  • Destinyyyy
??
dinamix
  • dinamix
i solve it when i do w^2-11w-80=0
dinamix
  • dinamix
we have 2 solution w(1) = -5 and w(2) = 16
dinamix
  • dinamix
u have too check it cuz i am sure about it
dinamix
  • dinamix
@Destinyyyy did find like that or no ?
dinamix
  • dinamix
\[\frac{ 11\pm \sqrt{121+320} }{ 2 }\]
Destinyyyy
  • Destinyyyy
I havent read a thing youve said... x= 5,1 x=-2,8
Destinyyyy
  • Destinyyyy
Correct?
Destinyyyy
  • Destinyyyy
I factored
Destinyyyy
  • Destinyyyy
???
dinamix
  • dinamix
u have 2 find 6 nomber to solve this problem 8;-2;5;1;16;-5
Destinyyyy
  • Destinyyyy
Why 6 numbers?
Destinyyyy
  • Destinyyyy
The last one I did like this was 2 numbers
Destinyyyy
  • Destinyyyy
I dont count the w only the x's
Destinyyyy
  • Destinyyyy
x= 5,-2,8 I should have one more step
Destinyyyy
  • Destinyyyy
@jim_thompson5910
dinamix
  • dinamix
w^2-11w-80 = 0 i find 2 numbers is -5 and 16 this only solution of W w----> x^2-6x we have find x now w=16 and w=x^2-6x------> x^2-6x=16 and also for -5 we solve this equation x^2-6x-16=0 and x^2-6x+5=0 and we find x
Destinyyyy
  • Destinyyyy
Yeah I already found x
Destinyyyy
  • Destinyyyy
x= 5 and 1 x= -2 and 8
Destinyyyy
  • Destinyyyy
I should have another step where I do x^2
dinamix
  • dinamix
yup this
dinamix
  • dinamix
did u understand now
Destinyyyy
  • Destinyyyy
Are my answers correct? Are they the final answer?
dinamix
  • dinamix
yup u right
Destinyyyy
  • Destinyyyy
And there are no more steps?
dinamix
  • dinamix
yeah
Destinyyyy
  • Destinyyyy
They are right.. I have two more problems
dinamix
  • dinamix
u still did understand or what ??o.O
Destinyyyy
  • Destinyyyy
I understand how to solve that last one.
Destinyyyy
  • Destinyyyy
Can you help me with two more?
Destinyyyy
  • Destinyyyy
Im going to post them in a new question and tag you.
dinamix
  • dinamix
my time is 1 :00 Am

Looking for something else?

Not the answer you are looking for? Search for more explanations.