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Destinyyyy
 one year ago
Help with 5 problems...
Destinyyyy
 one year ago
Help with 5 problems...

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.02 [7 3/2x] +5=21 [] are absolute value lines

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Not sure what to do next

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Nnesha @freckles @Vocaloid

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.2you're on the right track, but when we have absolute value signs, we must consider the positive and negative solutions to the equation so, going by what you have so far, we have:  7  3/2x  = 8, where   are the absolute value signs, with me so far?

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.2So, going from there, we need to write two different equations 7  3/2x = 8 and 7  3/2x = 8

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.2then we solve each one separately so, let's tackle the first one 7  3/2x = 8 first, subtract 7 from both sides and tell me what you get

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.2yup, now we divide both sides by (3/2)

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.2yup, so x = 2/3 now, we're only halfway done, there's another value of x that works for the equation. now we solve 7  (3/2)x = 8 using the same process as before. start by subtracting 7 from both sides

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.2yup, so x = 10 and x = 2/3 are your two solutions, good work ready for the next one?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Solve. [x+8] +9=7 same as the one before

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.2ah, not quite, there's an important rule to remember when it comes to absolute values. the absolute value of a mathematical expression cannot be negative as an example, if we have x = a, then a must be a positive number in order to have a solution so, looking at our problem, we first subtract 9 from each side to get x + 8 = 2 the absolute value of any quantity must be positive, so this has no solution

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.2does that make sense? are you ready to move to the next one?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes it does. I thought it was but wanted to make sure.. Solve using appropriate substitution. (x^2 6x)^2 11(x^2 6x) 30=0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I got 3+ square root 14 and 3+ square root 15 But its wrong...

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.2huh, this is a tricky one, hold on a moment

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.2well, I'm not sure if this is the right approach but...I'm guessing it wants us to substitute a variable for x^2 6x so, if we let a = x^2 6x, then our equation becomes a^2  11a  30 after we apply the quadratic formula we get dw:1440800955390:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I factored (w5)(w6)

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.2I'm not really sure if my thinking is correct and that factoring doesn't work, that would only work for positive 30, not 30 (w5)(w6) = w^2  11w + 30

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.2ah, I wish I could be of more help on this one :( I feel like I'm missing an obvious trick here @welshfella @SithsAndGiggles

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Its okay really. Your being super helpful :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Given that \(a^2  11a  30=0\) yields roots \(a=\dfrac{11\pm\sqrt{241}}{2}\), you can find the roots to \(x^2xa=0\) by applying the QF again.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0typo: \(x^2\color{red}6xa=0\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So... 1+ square root 5 over 2

dinamix
 one year ago
Best ResponseYou've already chosen the best response.02 solution w(1) = 5 and w(2) = 6

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay but how did you get to that?? Id like to know how to solve this

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The triangle is square root correct?

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0\[w =\frac{ 11 \pm \sqrt{121120} }{ 2} \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Except I have a positive 120

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0b^24ac = \[(11^2)  4*1*30\]

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0u looking for this w^211w+30 @Destinyyyy

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0its a negative 30 not positive...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The original problem contains a 30

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0what is your problem could u tell me what is equation

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Solve using appropriate substitution. (x^2 6x)^2 11(x^2 6x) 30=0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0w^2 11w 30=0 w^2> (x^26x)^2 w> x^2 6x

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0are u sure its 30 ? cuz like that we dont have good numbers

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Its actually 80 ... I miss read. So sorry

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Everything else is correct

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0so give me right equation without mistakes

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Solve using appropriate substitution. (x^2 6x)^2 11(x^2 6x) 80=0 I can screenshot it if you want

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0ok so w(1) = 5 and w(2) = 16

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0i solve it when i do w^211w80=0

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0we have 2 solution w(1) = 5 and w(2) = 16

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0u have too check it cuz i am sure about it

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0@Destinyyyy did find like that or no ?

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 11\pm \sqrt{121+320} }{ 2 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I havent read a thing youve said... x= 5,1 x=2,8

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0u have 2 find 6 nomber to solve this problem 8;2;5;1;16;5

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The last one I did like this was 2 numbers

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I dont count the w only the x's

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0x= 5,2,8 I should have one more step

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0w^211w80 = 0 i find 2 numbers is 5 and 16 this only solution of W w> x^26x we have find x now w=16 and w=x^26x> x^26x=16 and also for 5 we solve this equation x^26x16=0 and x^26x+5=0 and we find x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yeah I already found x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0x= 5 and 1 x= 2 and 8

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I should have another step where I do x^2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Are my answers correct? Are they the final answer?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0And there are no more steps?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0They are right.. I have two more problems

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0u still did understand or what ??o.O

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I understand how to solve that last one.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can you help me with two more?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Im going to post them in a new question and tag you.
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