Hi I've been trying this problem for 3 times, but still don't get it. This is my last try, so i would appreciate someone clarifying this problem for me

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Hi I've been trying this problem for 3 times, but still don't get it. This is my last try, so i would appreciate someone clarifying this problem for me

Mathematics
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How many significant figures would be re- tained in the solution to [(2 + 0.0031) + (413 / 12)]×(2.45×1.83) = 1. three 2. two 3. zero 4. five 5. one 6. four
I know is not 5 even though the 2 is one digit
also know is not zero because there are numbers with higher digits than 0

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and finally I know is not five just because
so my only possible answers are: number 1, or number 2
http://www.usca.edu/chemistry/genchem/sigfig2.htm
that doesn't really help
i was there already
According to the link above the following information is relevant to your problem. When adding or subtracting numbers, count the NUMBER OF DECIMAL PLACES to determine the number of significant figures. The answer cannot CONTAIN MORE PLACES AFTER THE DECIMAL POINT THAN THE SMALLEST NUMBER OF DECIMAL PLACES in the numbers being added or subtracted. When multiplying or dividing numbers, count the NUMBER OF SIGNIFICANT FIGURES. The answer cannot CONTAIN MORE SIGNIFICANT FIGURES THAN THE NUMBER BEING MULTIPLIED OR DIVIDED with the LEAST NUMBER OF SIGNIFICANT FIGURES. This information tells exactly how to figure out the correct answer. Takes a bit of work on your part, but yes you can figure it out.
yeah I know, so the answer would be to solve the equation, and since the 2 has only 1 digit or significant figure the answer would be round to one digit
this means the equation would equal to 200
What equation? Equations have equal signs.
However the answer is not 1(or number 5)
I meant problem, I'm sorry
Maybe i read the question wrong, but thats what I need a guide
Explain how you went about eliminating options.
I tried #5, and it was wrong. I know that it is not five digits because there is no number with 5 digits, and if there was there is numbers with less digits.
and I'm not sure why it can't be three, two, or four digits
What was the result you got before rounding up to 200 (which you should not have done).
163.2880239
Mind showing how you got that step by step?
I plot the whole problem in the calculator
No, you shouldn't have.
but I know I first would have to solve whats inside the keys
or i don't know what they are called in english
You have to perform each operation one step at a time while following the rules for significant digits.
alright so: ((2+0.0031)+(41/12)=40
because i had to round up
to one digit right?
now I solve the whole thing 40×(2.45×1.83)=179.34
then I have to round up to 1 digit since 40 mis the lowest significant figure and it only has one digit
this means 179.34 rounds up to 200
right?
You should follow ORDER of OPERATIONS. Multiply BEFORE adding from left to right.
(2 + 0.0031) + (413 / 12)]×(2.45×1.83) =[(2+0.0031)+(413/12)]x(4.4835)
is that what you meant?
Okay, yes, we should keep track of parentheses as well. You should have gotten 4.48 for (2.45×1.83)
oh right because there is 3 digits in there
make sense
The result can only be accurate to two decimal places.
For that operation
[(2.0031)+(34.42)]x(4.4835)
The result of an operation can only be accurate to the number with the least amount of decimal places. In other words, you should not have decimal places when dividing whole numbers.
[(2+0.0031)+(34)]x(4.4835)
now I add the ones inside, right?
Yep, but add according to the rules.
it would be 2.0
i mean 2
the lowest is 2 thats why, so 2+34=36=40
[40]x(4.48)=179.2
What rule says to round 36 to 40?
40 has only 1 digit. I rounded to one digit because of the two
How many significant figures does 4.48 have?
3
By the way, you shouldn't round 36 to 40.
alright
so 36(4.48)=180
36 has two significant digits which means our result should have only two significant digtts.
let me try, I'm gonna submit
Yes! it was 2 thank you so much
you helped me understanding it. The calculator is worthless!
The calculator does not know how to deal with significant digits unless you program it to do so.
but i guess there is some calculators that do, right?
Perhaps Wolfram Alpha does, but you would still have to use a special program for it. It won't do it automatically.
The calculator doesn't know you want to round to significant digits.
yeah of course
Good luck with the rest of your homework. Have a good one.
Thank you! you too

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