This is the excercise: (363 × 1.48)/3.5-1.79 + 6.1 × 10^−1
However, my question is unralated the answer. Does 10^-1 out as a significant figure? and if it does, it would count as 1 digit, right?

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hmmm what's the question again?

Write 10^{-1} as a decimal, then it should be obvious to you.

\[(\frac{ (363*1.48) }{ 3.5-1.79 })+6.1*10^{-1}\]

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