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mathmath333
 one year ago
A Malaysia Airlines is going from kuala lumpur to amsterdam and stops
in dubai,jerusalem,sofia,rome and vienna on the way.
3 passangers enter the Airplane with 3different tickets.
How many different collection of tickets may they have?
mathmath333
 one year ago
A Malaysia Airlines is going from kuala lumpur to amsterdam and stops in dubai,jerusalem,sofia,rome and vienna on the way. 3 passangers enter the Airplane with 3different tickets. How many different collection of tickets may they have?

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mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1\(\large \color{black}{\begin{align} & \normalsize \text{A Malaysia Airlines is going from kuala lumpur to amsterdam and stops } \hspace{.33em}\\~\\ & \normalsize \text{ in dubai,jerusalem,sofia,rome and vienna on the way.} \hspace{.33em}\\~\\ & \normalsize \text{3 passangers enter the Airplane with 3different tickets.} \hspace{.33em}\\~\\ & \normalsize \text{ How many different collection of tickets may they have?.} \hspace{.33em}\\~\\ \end{align}}\)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4so how many total stops are there?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4Careful, amsterdam is also a stop, the final stop

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1i cannot see ur logo r u in invisible (stealth mode)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4there is no stealth mode must be some bug haha

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4good, so there are 6 stops and we're told that the 3 passengers are carrying different tickets

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4dw:1440807869323:dw

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4How many choices are there for passenger1 ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4dw:1440808107900:dw

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4after that, how many choices are there for the ticket of passenger2 ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4right, see if you can finish it off

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1answer given is 455 way too far.

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4Perhaps it has something to do with \(\dbinom{15}{3}\) notice that \(15=5+4+3+2+1\)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4if we consider the case that not all 3 passengers enter at the same start point

mathmate
 one year ago
Best ResponseYou've already chosen the best response.2Strange, I get 1330. Starting from Kuala Lumpur, there are 6 destinations, and progressively reduced for passengers embarking at later airports. First passenger can have a choice of 1+2+3+4+5+6=21 tickets. Second ha 20, and third 19. So, assuming name of passengers do not count (as different), we have 21*20*19/6=1330 possible collection of tickets.

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4Exactly, looks the passengers only enter at the 5 intermediate stops

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4no doubt question is ambiguous, as it stands, 1330 looks more correct to me !

mathmate
 one year ago
Best ResponseYou've already chosen the best response.2Ah, that's why, so 15*14*13/6=455, there we go! Thanks!

mathmate
 one year ago
Best ResponseYou've already chosen the best response.2"...on the way.3 passangers enter the Airplane with 3different tickets." But there is a stop after "on the way"!

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4thats good catch! probably it should read \(\large \color{black}{\begin{align} & \normalsize \text{A Malaysia Airlines is going from kuala lumpur to amsterdam and stops } \hspace{.33em}\\~\\ & \normalsize \text{ in dubai,jerusalem,sofia,rome and vienna. On the way,} \hspace{.33em}\\~\\ & \normalsize \text{3 passangers enter the Airplane with 3different tickets.} \hspace{.33em}\\~\\ & \normalsize \text{ How many different collection of tickets may they have?.} \hspace{.33em}\\~\\ \end{align}}\)

mathmate
 one year ago
Best ResponseYou've already chosen the best response.2@ganeshie8 $455 would be correct for your corrected version of the problem! lol

phi
 one year ago
Best ResponseYou've already chosen the best response.1I was puzzled. the first interpretation, where they can get on kuala lumpur there are 7C2 trips (pick two cities, order does not matter) and number of combinations is (7C2) C 3 = 1330 but if they get on after kuala lumpur it is (6C2) C 3 = 15C3 = 455
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