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AmTran_Bus
 one year ago
Need DE help!
AmTran_Bus
 one year ago
Need DE help!

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AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0dw:1440809128053:dw

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0So I do not have a clue what to do about the boundary equation.

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0But I can show you how I solved the original part.

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.1I'd try something like \(y(x) = Ae^{2x} + Be^{2x} + Cx + D\) Or, I might notice that \(r^{2}  4 = 0\) has solutions r = 2 and r = 2 and then forget about the C and D terms.

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0dw:1440809556496:dw is what I got. But I have no clue what a boundary is nor how to apply it.

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0and the book says that is right.

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.1?? Substitute x = 0 \(c_{1}e^{2(0)} + c_{2}e^{2(0)} = 2\) Now, find the first derivative and do it again. This gives two equations in two unknowns and you are nearly done.

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0So you gotta take deriv. and then substitute.

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.1If you want to use the second boundary condition, yes.

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0Ohhhhhh. That is where I am messing up.

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0Duh duh me. Thanks so much.

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0So 2=c1+c2 and 2= c1c2

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.1Shedding a little light is very rewarding.

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0Sure nuff. Especially since this is pchem.

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0Hum. So how where does the 2e^(2x) come from at the end @tkhunny ? I know 4=2c1 and so c1=2 and c2=0 so does that 2 just apply to both the coeff. and the e^whatever?

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.1"pchem"?! You have my sympathies. You CAN get through it.
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