If \(z = \frac{ \left\{ \sqrt{3} \right\}^2 - 2 \left\{ \sqrt{2} \right\}^2 }{ \left\{ \sqrt{3} \right\} - 2 \left\{ \sqrt{2} \right\} }\) find \(\lfloor z \rfloor\).

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If \(z = \frac{ \left\{ \sqrt{3} \right\}^2 - 2 \left\{ \sqrt{2} \right\}^2 }{ \left\{ \sqrt{3} \right\} - 2 \left\{ \sqrt{2} \right\} }\) find \(\lfloor z \rfloor\).

Mathematics
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Do you mean the absolute of \(z\)?
no, the floor function
so the integer when you round the answer down

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Other answers:

And the answer is not 0
Without using a calculator, right?
I tried with a calculator already, didn't give me the right answer.
What is the value that's given by the calculator?
0.9 (and a whole bunch of numbers after that but they don't affect the rounding)
Then the answer should be 0
Hey I think you've forgotten the minus sign :-)
Because the answer should be a inus value.....
*minus
@amilapsn nope, not -1 either :(
Sorry I got it wrong >_< the answer is positive..... Your answer is correct. Zero
@amilapsn not 0 either :( i think im going to give up on this problem
I think you should double check that you've got that question right. Otherwise zero should be the answer...

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