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zmudz

  • one year ago

If \(z = \frac{ \left\{ \sqrt{3} \right\}^2 - 2 \left\{ \sqrt{2} \right\}^2 }{ \left\{ \sqrt{3} \right\} - 2 \left\{ \sqrt{2} \right\} }\) find \(\lfloor z \rfloor\).

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  1. ahsome
    • one year ago
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    Do you mean the absolute of \(z\)?

  2. zmudz
    • one year ago
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    no, the floor function

  3. zmudz
    • one year ago
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    so the integer when you round the answer down

  4. zmudz
    • one year ago
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    And the answer is not 0

  5. amilapsn
    • one year ago
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    Without using a calculator, right?

  6. zmudz
    • one year ago
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    I tried with a calculator already, didn't give me the right answer.

  7. amilapsn
    • one year ago
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    What is the value that's given by the calculator?

  8. zmudz
    • one year ago
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    0.9 (and a whole bunch of numbers after that but they don't affect the rounding)

  9. amilapsn
    • one year ago
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    Then the answer should be 0

  10. amilapsn
    • one year ago
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    Hey I think you've forgotten the minus sign :-)

  11. amilapsn
    • one year ago
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    Because the answer should be a inus value.....

  12. amilapsn
    • one year ago
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    *minus

  13. zmudz
    • one year ago
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    @amilapsn nope, not -1 either :(

  14. amilapsn
    • one year ago
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    Sorry I got it wrong >_< the answer is positive..... Your answer is correct. Zero

  15. zmudz
    • one year ago
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    @amilapsn not 0 either :( i think im going to give up on this problem

  16. amilapsn
    • one year ago
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    I think you should double check that you've got that question right. Otherwise zero should be the answer...

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