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## zmudz one year ago If $$z = \frac{ \left\{ \sqrt{3} \right\}^2 - 2 \left\{ \sqrt{2} \right\}^2 }{ \left\{ \sqrt{3} \right\} - 2 \left\{ \sqrt{2} \right\} }$$ find $$\lfloor z \rfloor$$.

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1. anonymous

Do you mean the absolute of $$z$$?

2. zmudz

no, the floor function

3. zmudz

so the integer when you round the answer down

4. zmudz

And the answer is not 0

5. amilapsn

Without using a calculator, right?

6. zmudz

I tried with a calculator already, didn't give me the right answer.

7. amilapsn

What is the value that's given by the calculator?

8. zmudz

0.9 (and a whole bunch of numbers after that but they don't affect the rounding)

9. amilapsn

Then the answer should be 0

10. amilapsn

Hey I think you've forgotten the minus sign :-)

11. amilapsn

Because the answer should be a inus value.....

12. amilapsn

*minus

13. zmudz

@amilapsn nope, not -1 either :(

14. amilapsn

Sorry I got it wrong >_< the answer is positive..... Your answer is correct. Zero

15. zmudz

@amilapsn not 0 either :( i think im going to give up on this problem

16. amilapsn

I think you should double check that you've got that question right. Otherwise zero should be the answer...

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