Destinyyyy
  • Destinyyyy
Check my answers.. I know one of them is incorrect..
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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Destinyyyy
  • Destinyyyy
Solve. 4[4- 3/2x] +9=41 [] is absolute value I got x=8 and -8/3
Destinyyyy
  • Destinyyyy
Find all the real solutions. 6x^2/3 -41x ^1/3 -7=0 I got x= -1/216 and 343
jim_thompson5910
  • jim_thompson5910
If the first equation is \[\Large 4\left|4-\frac{3}{2}x\right|+9 = 41\] I'm getting x = 8 or x = -8/3 also. So both of your answers are correct (assuming I wrote the problem above correctly)

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Destinyyyy
  • Destinyyyy
3. Solve the polynomial and zero-product. 98x-49= 2x^3 -x^2 I got x=1/2 and -7 and 7
Destinyyyy
  • Destinyyyy
Yes thats the correct problem
Destinyyyy
  • Destinyyyy
4. Solve rational exponent. (x-6) ^3/2 =125 I got x=31 5. Solve radical equation. Square root 2x+11 =x+4 - the square root has 11 under it. I got -3 +- 3i square root 2
jim_thompson5910
  • jim_thompson5910
`Find all the real solutions.` `6x^2/3 -41x ^1/3 -7=0` `I got x= -1/216 and 343` I'm getting the same solutions as well
Destinyyyy
  • Destinyyyy
Okay
jim_thompson5910
  • jim_thompson5910
`3. Solve the polynomial and zero-product.` `98x-49= 2x^3 -x^2` `I got x=1/2 and -7 and 7` all three solutions are correct
jim_thompson5910
  • jim_thompson5910
#4 is correct but #5 is not correct
Destinyyyy
  • Destinyyyy
Okay... Hmmm where did I mess up :/
Destinyyyy
  • Destinyyyy
x^2 +6x+27=0 Is that part correct??
jim_thompson5910
  • jim_thompson5910
#5 is this problem right? \[\Large \sqrt{2x+11} =x+4\]
Destinyyyy
  • Destinyyyy
Yes
jim_thompson5910
  • jim_thompson5910
Square both sides to get... \[\Large \sqrt{2x+11} =x+4\] \[\Large \left(\sqrt{2x+11}\right)^2 =(x+4)^2\] \[\Large 2x+11 =x^2+8x+16\]
Destinyyyy
  • Destinyyyy
Yep I have that
Destinyyyy
  • Destinyyyy
I see where i messed up I added 11 instead of -11
jim_thompson5910
  • jim_thompson5910
Then get everything to one side \[\Large 2x+11 =x^2+8x+16\] \[\Large 2x+11{\color{red}{-11}} =x^2+8x+16{\color{red}{-11}}\] \[\Large 2x=x^2+8x+5\] \[\Large 2x{\color{red}{-2x}}=x^2+8x+5{\color{red}{-2x}}\] \[\Large 0=x^2+6x+5\] \[\Large x^2+6x+5=0\]
Destinyyyy
  • Destinyyyy
Yeah have that now
jim_thompson5910
  • jim_thompson5910
ok great
jim_thompson5910
  • jim_thompson5910
once you have your possible solutions, check them back in the original equation
Destinyyyy
  • Destinyyyy
x=-1 and x=-5
jim_thompson5910
  • jim_thompson5910
check each of those possible solutions back in the original equation
Destinyyyy
  • Destinyyyy
only -1 is true
Destinyyyy
  • Destinyyyy
Thank you!
jim_thompson5910
  • jim_thompson5910
yes -5 is extraneous

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