## Destinyyyy one year ago Check my answers.. I know one of them is incorrect..

1. Destinyyyy

Solve. 4[4- 3/2x] +9=41 [] is absolute value I got x=8 and -8/3

2. Destinyyyy

Find all the real solutions. 6x^2/3 -41x ^1/3 -7=0 I got x= -1/216 and 343

3. jim_thompson5910

If the first equation is $\Large 4\left|4-\frac{3}{2}x\right|+9 = 41$ I'm getting x = 8 or x = -8/3 also. So both of your answers are correct (assuming I wrote the problem above correctly)

4. Destinyyyy

3. Solve the polynomial and zero-product. 98x-49= 2x^3 -x^2 I got x=1/2 and -7 and 7

5. Destinyyyy

Yes thats the correct problem

6. Destinyyyy

4. Solve rational exponent. (x-6) ^3/2 =125 I got x=31 5. Solve radical equation. Square root 2x+11 =x+4 - the square root has 11 under it. I got -3 +- 3i square root 2

7. jim_thompson5910

Find all the real solutions. 6x^2/3 -41x ^1/3 -7=0 I got x= -1/216 and 343 I'm getting the same solutions as well

8. Destinyyyy

Okay

9. jim_thompson5910

3. Solve the polynomial and zero-product. 98x-49= 2x^3 -x^2 I got x=1/2 and -7 and 7 all three solutions are correct

10. jim_thompson5910

#4 is correct but #5 is not correct

11. Destinyyyy

Okay... Hmmm where did I mess up :/

12. Destinyyyy

x^2 +6x+27=0 Is that part correct??

13. jim_thompson5910

#5 is this problem right? $\Large \sqrt{2x+11} =x+4$

14. Destinyyyy

Yes

15. jim_thompson5910

Square both sides to get... $\Large \sqrt{2x+11} =x+4$ $\Large \left(\sqrt{2x+11}\right)^2 =(x+4)^2$ $\Large 2x+11 =x^2+8x+16$

16. Destinyyyy

Yep I have that

17. Destinyyyy

I see where i messed up I added 11 instead of -11

18. jim_thompson5910

Then get everything to one side $\Large 2x+11 =x^2+8x+16$ $\Large 2x+11{\color{red}{-11}} =x^2+8x+16{\color{red}{-11}}$ $\Large 2x=x^2+8x+5$ $\Large 2x{\color{red}{-2x}}=x^2+8x+5{\color{red}{-2x}}$ $\Large 0=x^2+6x+5$ $\Large x^2+6x+5=0$

19. Destinyyyy

Yeah have that now

20. jim_thompson5910

ok great

21. jim_thompson5910

once you have your possible solutions, check them back in the original equation

22. Destinyyyy

x=-1 and x=-5

23. jim_thompson5910

check each of those possible solutions back in the original equation

24. Destinyyyy

only -1 is true

25. Destinyyyy

Thank you!

26. jim_thompson5910

yes -5 is extraneous