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Destinyyyy
 one year ago
Check my answers.. I know one of them is incorrect..
Destinyyyy
 one year ago
Check my answers.. I know one of them is incorrect..

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Solve. 4[4 3/2x] +9=41 [] is absolute value I got x=8 and 8/3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Find all the real solutions. 6x^2/3 41x ^1/3 7=0 I got x= 1/216 and 343

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1If the first equation is \[\Large 4\left4\frac{3}{2}x\right+9 = 41\] I'm getting x = 8 or x = 8/3 also. So both of your answers are correct (assuming I wrote the problem above correctly)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.03. Solve the polynomial and zeroproduct. 98x49= 2x^3 x^2 I got x=1/2 and 7 and 7

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes thats the correct problem

anonymous
 one year ago
Best ResponseYou've already chosen the best response.04. Solve rational exponent. (x6) ^3/2 =125 I got x=31 5. Solve radical equation. Square root 2x+11 =x+4  the square root has 11 under it. I got 3 + 3i square root 2

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1`Find all the real solutions.` `6x^2/3 41x ^1/3 7=0` `I got x= 1/216 and 343` I'm getting the same solutions as well

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1`3. Solve the polynomial and zeroproduct.` `98x49= 2x^3 x^2` `I got x=1/2 and 7 and 7` all three solutions are correct

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1#4 is correct but #5 is not correct

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay... Hmmm where did I mess up :/

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0x^2 +6x+27=0 Is that part correct??

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1#5 is this problem right? \[\Large \sqrt{2x+11} =x+4\]

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1Square both sides to get... \[\Large \sqrt{2x+11} =x+4\] \[\Large \left(\sqrt{2x+11}\right)^2 =(x+4)^2\] \[\Large 2x+11 =x^2+8x+16\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I see where i messed up I added 11 instead of 11

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1Then get everything to one side \[\Large 2x+11 =x^2+8x+16\] \[\Large 2x+11{\color{red}{11}} =x^2+8x+16{\color{red}{11}}\] \[\Large 2x=x^2+8x+5\] \[\Large 2x{\color{red}{2x}}=x^2+8x+5{\color{red}{2x}}\] \[\Large 0=x^2+6x+5\] \[\Large x^2+6x+5=0\]

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1once you have your possible solutions, check them back in the original equation

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1check each of those possible solutions back in the original equation

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1yes 5 is extraneous
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