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Destinyyyy

  • one year ago

Check my answers.. I know one of them is incorrect..

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  1. Destinyyyy
    • one year ago
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    Solve. 4[4- 3/2x] +9=41 [] is absolute value I got x=8 and -8/3

  2. Destinyyyy
    • one year ago
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    Find all the real solutions. 6x^2/3 -41x ^1/3 -7=0 I got x= -1/216 and 343

  3. jim_thompson5910
    • one year ago
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    If the first equation is \[\Large 4\left|4-\frac{3}{2}x\right|+9 = 41\] I'm getting x = 8 or x = -8/3 also. So both of your answers are correct (assuming I wrote the problem above correctly)

  4. Destinyyyy
    • one year ago
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    3. Solve the polynomial and zero-product. 98x-49= 2x^3 -x^2 I got x=1/2 and -7 and 7

  5. Destinyyyy
    • one year ago
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    Yes thats the correct problem

  6. Destinyyyy
    • one year ago
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    4. Solve rational exponent. (x-6) ^3/2 =125 I got x=31 5. Solve radical equation. Square root 2x+11 =x+4 - the square root has 11 under it. I got -3 +- 3i square root 2

  7. jim_thompson5910
    • one year ago
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    `Find all the real solutions.` `6x^2/3 -41x ^1/3 -7=0` `I got x= -1/216 and 343` I'm getting the same solutions as well

  8. Destinyyyy
    • one year ago
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    Okay

  9. jim_thompson5910
    • one year ago
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    `3. Solve the polynomial and zero-product.` `98x-49= 2x^3 -x^2` `I got x=1/2 and -7 and 7` all three solutions are correct

  10. jim_thompson5910
    • one year ago
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    #4 is correct but #5 is not correct

  11. Destinyyyy
    • one year ago
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    Okay... Hmmm where did I mess up :/

  12. Destinyyyy
    • one year ago
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    x^2 +6x+27=0 Is that part correct??

  13. jim_thompson5910
    • one year ago
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    #5 is this problem right? \[\Large \sqrt{2x+11} =x+4\]

  14. Destinyyyy
    • one year ago
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    Yes

  15. jim_thompson5910
    • one year ago
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    Square both sides to get... \[\Large \sqrt{2x+11} =x+4\] \[\Large \left(\sqrt{2x+11}\right)^2 =(x+4)^2\] \[\Large 2x+11 =x^2+8x+16\]

  16. Destinyyyy
    • one year ago
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    Yep I have that

  17. Destinyyyy
    • one year ago
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    I see where i messed up I added 11 instead of -11

  18. jim_thompson5910
    • one year ago
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    Then get everything to one side \[\Large 2x+11 =x^2+8x+16\] \[\Large 2x+11{\color{red}{-11}} =x^2+8x+16{\color{red}{-11}}\] \[\Large 2x=x^2+8x+5\] \[\Large 2x{\color{red}{-2x}}=x^2+8x+5{\color{red}{-2x}}\] \[\Large 0=x^2+6x+5\] \[\Large x^2+6x+5=0\]

  19. Destinyyyy
    • one year ago
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    Yeah have that now

  20. jim_thompson5910
    • one year ago
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    ok great

  21. jim_thompson5910
    • one year ago
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    once you have your possible solutions, check them back in the original equation

  22. Destinyyyy
    • one year ago
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    x=-1 and x=-5

  23. jim_thompson5910
    • one year ago
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    check each of those possible solutions back in the original equation

  24. Destinyyyy
    • one year ago
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    only -1 is true

  25. Destinyyyy
    • one year ago
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    Thank you!

  26. jim_thompson5910
    • one year ago
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    yes -5 is extraneous

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