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AmTran_Bus
 one year ago
Help combine equations!! urgent!
AmTran_Bus
 one year ago
Help combine equations!! urgent!

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AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0dw:1440812074262:dw

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0dw:1440812141980:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Are you trying to solve for both \(C_1\) and \(C_2\)?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well. The first step is to rearrange the equation get one variable by itself. I can show the first one: \[1=C_1+C_2\]\[C_1=1C_2\]Can you do for the other equation?

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0Well, isn't the other one already in terms of c1?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Exactly. Now, can you susbtitue them together?

marigirl
 one year ago
Best ResponseYou've already chosen the best response.1\[1=c _{1}+c _{2}\] \[c _{1}=\frac{ 3c _{2} }{ 2 }\] now we have \[1= \frac{ 3c _{2} }{ 2 }+c _{2}\] now solve for c2 made both terms on right with same denominator \[2= \frac{ 3c _{2} }{ 2 } + \frac{ 2c }{ 2 }\]

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0dw:1440812432810:dw

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0nice thanks @marigirl

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Now, you can substitute them together as: \[1C_2=\frac{3\times C_2}{2}\]

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0Just like marigirl :)

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0Actually im confused again can one of you show me the rest?
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