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anonymous

  • one year ago

An electric field is constant at every point on a square surface that is 0.80 m on a side. This field has a magnitude of 8.1 N/C and is oriented at an angle of 35° with respect to the surface, as the drawing shows. Calculate the electric flux ΦE passing through the surface.

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  1. anonymous
    • one year ago
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    Is this calculus physics or physics with no calculus?

  2. anonymous
    • one year ago
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    Electric flux=electric field x area x cos(theta)

  3. anonymous
    • one year ago
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    =8.1 N/C x (0.80m)^2 x cos35

  4. IrishBoy123
    • one year ago
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    you need to show the drawing or explain "oriented at an angle of 35° with respect to the surface" more fully the relevant angle could be 35 deg or 55 deg.|dw:1440861776328:dw|

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