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anonymous

  • one year ago

1+5(x-8)≤2-(x+5) ?

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  1. cookiemonster2412
    • one year ago
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    You have to distribute first.

  2. anonymous
    • one year ago
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    I got 1+5x-40≤2-(x+5)

  3. cookiemonster2412
    • one year ago
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    Okay now distribute on the other side.

  4. anonymous
    • one year ago
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    ._. Doesn't 2 have to be by the parentheses for me to distribute?

  5. cookiemonster2412
    • one year ago
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    You distribute the negative. So negative times x becomes -x

  6. cookiemonster2412
    • one year ago
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    Do you get it?

  7. anonymous
    • one year ago
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    So would that be 1+5x-40≤2-x+5?

  8. anonymous
    • one year ago
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    Kinda...

  9. cookiemonster2412
    • one year ago
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    It would be negative 5 since you're multiplying by a negative

  10. anonymous
    • one year ago
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    Okay, so 1+5-40≤2-x-5...

  11. cookiemonster2412
    • one year ago
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    Yes. Now combine like terms.

  12. anonymous
    • one year ago
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    How do I do that if both X's are on opposite sides? ._. I apologize, I'm really bad in math.

  13. cookiemonster2412
    • one year ago
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    It's fine. On the right side you can combine the 2 and -5

  14. cookiemonster2412
    • one year ago
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    What did you get?

  15. anonymous
    • one year ago
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    okay, 1+5x-40≤-x-3

  16. cookiemonster2412
    • one year ago
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    Now on the left side you can combine 1 and -40

  17. anonymous
    • one year ago
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    5x-39≤-x-3

  18. cookiemonster2412
    • one year ago
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    You're trying to get x by itself so you have to add x to both sides

  19. cookiemonster2412
    • one year ago
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    |dw:1440733664805:dw|

  20. anonymous
    • one year ago
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    6x-39≤-3

  21. cookiemonster2412
    • one year ago
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    Good. Now you add 39 to both sides.

  22. anonymous
    • one year ago
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    6x≤36

  23. cookiemonster2412
    • one year ago
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    Yes! Now to get x by itself you divide both sides by 6

  24. cookiemonster2412
    • one year ago
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    |dw:1440733832976:dw|

  25. anonymous
    • one year ago
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    X≤6

  26. anonymous
    • one year ago
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    Ahhhh (: thank you so much!

  27. cookiemonster2412
    • one year ago
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    Yes! You're welcome. :)

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