## anonymous one year ago What is the standard form of the equation of a circle with its center at (2, -3) and passing through the point (-2, 0)?

1. Nnesha

standard form equation of circle is $\huge\rm (x-h)^2+(y-k)^2=r^2$ where (h,k) is the center and substitute (x,y) for (-2,10) to find radius

2. Nnesha

let me know if you din't get it

3. Nnesha

didn't*

4. anonymous

Ya I don't sorry

5. Nnesha

alright so center point is (2,-3) which is (h,k) and (x,y) point is (-2,0) so replace (h,k) and x y with their values

6. Nnesha

$\huge\rm (\color{ReD}{h},\color{blue}{k}),(\color{reD}{2},\color{blue}{-3})$ first coordinate is h 2nd one is k

7. Nnesha

$\huge\rm (x-h)^2+(y-k)^2=r^2$ so replace h with 2 and k with -3

8. Nnesha

(-2, 0) what is x and y in this order pair ?

9. anonymous

-3,2

10. Nnesha

that's the center point in this order piar (-2,0) which one is x-coordinate or which one is y-coordinate

11. Nnesha

?

12. anonymous

2 is the x

13. Nnesha

it's -2 and yes now substitute $\huge\rm (-2-2)^2+(0-(-3))^2=r^2$ solve for r

14. anonymous

-7?

15. Nnesha

nope i didn't get that

16. Nnesha

solve for r^2 **