anonymous
  • anonymous
What is the standard form of the equation of a circle with its center at (2, -3) and passing through the point (-2, 0)?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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Nnesha
  • Nnesha
standard form equation of circle is \[\huge\rm (x-h)^2+(y-k)^2=r^2\] where (h,k) is the center and substitute (x,y) for (-2,10) to find radius
Nnesha
  • Nnesha
let me know if you din't get it
Nnesha
  • Nnesha
didn't*

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anonymous
  • anonymous
Ya I don't sorry
Nnesha
  • Nnesha
alright so center point is (2,-3) which is (h,k) and (x,y) point is (-2,0) so replace (h,k) and x y with their values
Nnesha
  • Nnesha
\[\huge\rm (\color{ReD}{h},\color{blue}{k}),(\color{reD}{2},\color{blue}{-3})\] first coordinate is h 2nd one is k
Nnesha
  • Nnesha
\[\huge\rm (x-h)^2+(y-k)^2=r^2\] so replace h with 2 and k with -3
Nnesha
  • Nnesha
(-2, 0) what is x and y in this order pair ?
anonymous
  • anonymous
-3,2
Nnesha
  • Nnesha
that's the center point in this order piar (-2,0) which one is x-coordinate or which one is y-coordinate
Nnesha
  • Nnesha
?
anonymous
  • anonymous
2 is the x
Nnesha
  • Nnesha
it's -2 and yes now substitute \[\huge\rm (-2-2)^2+(0-(-3))^2=r^2\] solve for r
anonymous
  • anonymous
-7?
Nnesha
  • Nnesha
nope i didn't get that
Nnesha
  • Nnesha
solve for r^2 **

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