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anonymous

  • one year ago

What is the standard form of the equation of a circle with its center at (2, -3) and passing through the point (-2, 0)?

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  1. Nnesha
    • one year ago
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    standard form equation of circle is \[\huge\rm (x-h)^2+(y-k)^2=r^2\] where (h,k) is the center and substitute (x,y) for (-2,10) to find radius

  2. Nnesha
    • one year ago
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    let me know if you din't get it

  3. Nnesha
    • one year ago
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    didn't*

  4. anonymous
    • one year ago
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    Ya I don't sorry

  5. Nnesha
    • one year ago
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    alright so center point is (2,-3) which is (h,k) and (x,y) point is (-2,0) so replace (h,k) and x y with their values

  6. Nnesha
    • one year ago
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    \[\huge\rm (\color{ReD}{h},\color{blue}{k}),(\color{reD}{2},\color{blue}{-3})\] first coordinate is h 2nd one is k

  7. Nnesha
    • one year ago
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    \[\huge\rm (x-h)^2+(y-k)^2=r^2\] so replace h with 2 and k with -3

  8. Nnesha
    • one year ago
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    (-2, 0) what is x and y in this order pair ?

  9. anonymous
    • one year ago
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    -3,2

  10. Nnesha
    • one year ago
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    that's the center point in this order piar (-2,0) which one is x-coordinate or which one is y-coordinate

  11. Nnesha
    • one year ago
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    ?

  12. anonymous
    • one year ago
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    2 is the x

  13. Nnesha
    • one year ago
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    it's -2 and yes now substitute \[\huge\rm (-2-2)^2+(0-(-3))^2=r^2\] solve for r

  14. anonymous
    • one year ago
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    -7?

  15. Nnesha
    • one year ago
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    nope i didn't get that

  16. Nnesha
    • one year ago
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    solve for r^2 **

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