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anonymous

  • one year ago

Linear equation A= x + y + z/3 solve for y

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  1. anonymous
    • one year ago
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    I got the answer y = 3A-x-z but only cause i followed an example so im kind of confused.

  2. anonymous
    • one year ago
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    same here

  3. Rizags
    • one year ago
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    thats not the right answer

  4. Rizags
    • one year ago
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    first move all varibales to one side, leaving y alone

  5. anonymous
    • one year ago
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    On the answer sheet it said it was lol but my teacher said it could be more than one answer

  6. anonymous
    • one year ago
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    which is all ready done

  7. Rizags
    • one year ago
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    Wait up, is it \[A= \frac{x+y+z}{3}\] or \[A= x+ y + \frac{z}{3}\]

  8. anonymous
    • one year ago
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    the first one

  9. Rizags
    • one year ago
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    ahh, then, yes your answer is correct

  10. Rizags
    • one year ago
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    first multiply both sides by 3 to get \[3A = x+y+z\]

  11. Rizags
    • one year ago
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    then subtract x and z \[3A-x-z=y\]

  12. anonymous
    • one year ago
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    Thats the part i get confused where am i subtracting x and z?

  13. anonymous
    • one year ago
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    y=\[\frac{ a-z-x }{ 3 }\]

  14. anonymous
    • one year ago
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    no your not

  15. Rizags
    • one year ago
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    from here: \[3A = x+y+z\] you subtract x and z

  16. anonymous
    • one year ago
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    no you divide by three to get y alone

  17. anonymous
    • one year ago
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    ohhh i see because youre trying to get the y alone

  18. anonymous
    • one year ago
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    yah

  19. anonymous
    • one year ago
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    and what ever is on the other side is y

  20. anonymous
    • one year ago
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    okay thank you both :)

  21. anonymous
    • one year ago
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    no problem

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