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anonymous
 one year ago
Okay, really struggling on this one :/ I just need hep finishing the problem. x1/(5x^2  8x +3) times 4(5x  3)/x11
anonymous
 one year ago
Okay, really struggling on this one :/ I just need hep finishing the problem. x1/(5x^2  8x +3) times 4(5x  3)/x11

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@zepdrix Let me know if I'm annoying you at anytime!!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@nincompoop please help, I'll fan & medal you (:

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1What's going on? Factoring stuff and simplify again?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well, I'm just stuck here :/ I can't find a way to further factor it! I already factored a simplified some of it.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Oh it's one of these types :O

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Uhoh, that doesnt sound good ;(

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1dw:1440828539698:dwHave you learned this goofy method before?

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Ehhh scratch that, let's do factor by GROUPING instead :) That's a better approach anyway.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ohh I know how to do that ;p But I thought you needed 4 terms?

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Hmm :d no. You start with 3 terms, and yes, you'll break them into 4 terms in order to do your grouping.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1So what you're doing is, splitting the middle term in some clever way so you can have nice groups.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1\[\large\rm 5x^2\color{orangered}{8x}+3\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay, then I haven't done this before haha. Uhmm I really have no idea :/

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1We'll multiply A and C, giving us 15. Factors of 15 that add to 8? Hmm

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.115*1 = 15 15 + 1 = 16 Hmm those didn't work

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.15 * 3 = 15 5 + 3 = 8 Hmm it didn't give us 8 though D:

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0;( I have no clue how to get 8 from the factors of 15..

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh!!! Lol why do I always miss this?? 5 and 3! lol

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Ok good. So that's telling us that we want to rewrite 8x as 5x and 3x.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1\[\large\rm 5x^2\color{orangered}{8x}+3\]\[\large\rm 5x^2\color{orangered}{5x3x}+3\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ohh okay I remember this! And the groups are (5x^2  5x) and (3x +3)

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1And no, it doesn't matter which order you write them in. If you had written 3x 5x in that order, we would end up with the same result. So don't worry about that.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Yes. And please please please try to get in the habit of putting a `plus sign` between the groups. Very annoying mistake that a lot of students make lol

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1(5x^25x) + (3x+3) k good :) now factor it out

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh, sorry! So I got 5(x^2  x) + 3(x +1)

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1\[\large\rm 5(\color{orangered}{x^2  x}) + 3(x +1)\]Well, there is more in this orange stuff. The two terms in orange still share something in common. Taking the 5 out was good, but there is moar.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh! Okay so it's 5x(x1) + 3(x+1)

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Mmmm k good.\[\large\rm 5x(\color{orangered}{x1}) + 3(\color{orangered}{x +1})\]But how do we get these orange parts to match up? Hmm maybe we forgot to pull something out the second set of brackets?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.05x(x1) + 3(x+1) lol (:

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1\[\large\rm \left[5x\color{orangered}{(x1)}3\color{orangered}{(x1)}\right]\]OK good :O We factored the two brackets completely. I artificially placed some square brackets. We now want to pull anything similar from both terms out of the square brackets.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Hint Hint, I colorcoded the thing we're pulling out :3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Lol so we just get 5x3 (:

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1\[\large\rm \left[5x\color{orangered}{(x1)}3\color{orangered}{(x1)}\right]\quad=\quad\color{orangered}{(x1)}\left[5x3\right]\]Well we can't forget about the factor we pulled out, ya? But yes, we end up with only 5x3 in the square brackets.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1You don't have to use square brackets if you don't want :P That was just help explain the process. So our final result from factoring is:\[\large\rm 5x^28x+3\quad=\quad (x1)(5x3)\]

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Did the factoring from the square brackets step make sense? :o I know that one can be a little tricky.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ohhh my bad lol i just wasnt thinking, for some reason I thought the (x1) just canceled out.. Lol so let me see if I can simplify now

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yayyyy! I solved it (: I got 4/x11 thank you bunches
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