anonymous
  • anonymous
Okay, really struggling on this one :/ I just need hep finishing the problem. x-1/(5x^2 - 8x +3) times 4(5x - 3)/x-11
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
@zepdrix Let me know if I'm annoying you at anytime!!
anonymous
  • anonymous
@nincompoop please help, I'll fan & medal you (:
zepdrix
  • zepdrix
you and your ways -_-

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zepdrix
  • zepdrix
What's going on? Factoring stuff and simplify again?
anonymous
  • anonymous
Well, I'm just stuck here :/ I can't find a way to further factor it! I already factored a simplified some of it.
zepdrix
  • zepdrix
Oh it's one of these types :O
anonymous
  • anonymous
Uh-oh, that doesnt sound good ;(
zepdrix
  • zepdrix
|dw:1440828539698:dw|Have you learned this goofy method before?
anonymous
  • anonymous
Not at all!?
zepdrix
  • zepdrix
Ehhh scratch that, let's do factor by GROUPING instead :) That's a better approach anyway.
anonymous
  • anonymous
Ohh I know how to do that ;p But I thought you needed 4 terms?
zepdrix
  • zepdrix
Hmm :d no. You start with 3 terms, and yes, you'll break them into 4 terms in order to do your grouping.
zepdrix
  • zepdrix
So what you're doing is, splitting the middle term in some clever way so you can have nice groups.
zepdrix
  • zepdrix
\[\large\rm 5x^2\color{orangered}{-8x}+3\]
anonymous
  • anonymous
Okay, then I haven't done this before haha. Uhmm I really have no idea :/
zepdrix
  • zepdrix
We'll multiply A and C, giving us 15. Factors of 15 that add to -8? Hmm
zepdrix
  • zepdrix
15*1 = 15 15 + 1 = 16 Hmm those didn't work
anonymous
  • anonymous
5 and 3
zepdrix
  • zepdrix
5 * 3 = 15 5 + 3 = 8 Hmm it didn't give us -8 though D:
anonymous
  • anonymous
;( I have no clue how to get -8 from the factors of 15..
anonymous
  • anonymous
Oh!!! Lol why do I always miss this?? -5 and -3! lol
zepdrix
  • zepdrix
Ok good. So that's telling us that we want to rewrite -8x as -5x and -3x.
zepdrix
  • zepdrix
\[\large\rm 5x^2\color{orangered}{-8x}+3\]\[\large\rm 5x^2\color{orangered}{-5x-3x}+3\]
anonymous
  • anonymous
Ohh okay I remember this! And the groups are (5x^2 - 5x) and (-3x +3)
zepdrix
  • zepdrix
And no, it doesn't matter which order you write them in. If you had written -3x -5x in that order, we would end up with the same result. So don't worry about that.
zepdrix
  • zepdrix
Yes. And please please please try to get in the habit of putting a `plus sign` between the groups. Very annoying mistake that a lot of students make lol
zepdrix
  • zepdrix
(5x^2-5x) + (-3x+3) k good :) now factor it out
anonymous
  • anonymous
Oh, sorry! So I got 5(x^2 - x) + 3(-x +1)
zepdrix
  • zepdrix
MOAR :O moar stuff
anonymous
  • anonymous
What do you mean?
zepdrix
  • zepdrix
\[\large\rm 5(\color{orangered}{x^2 - x}) + 3(-x +1)\]Well, there is more in this orange stuff. The two terms in orange still share something in common. Taking the 5 out was good, but there is moar.
anonymous
  • anonymous
Oh! Okay so it's 5x(x-1) + 3(-x+1)
zepdrix
  • zepdrix
Mmmm k good.\[\large\rm 5x(\color{orangered}{x-1}) + 3(\color{orangered}{-x +1})\]But how do we get these orange parts to match up? Hmm maybe we forgot to pull something out the second set of brackets?
anonymous
  • anonymous
5x(x-1) + -3(x+1) lol (:
zepdrix
  • zepdrix
\[\large\rm \left[5x\color{orangered}{(x-1)}-3\color{orangered}{(x-1)}\right]\]OK good :O We factored the two brackets completely. I artificially placed some square brackets. We now want to pull anything similar from both terms out of the square brackets.
zepdrix
  • zepdrix
Hint Hint, I color-coded the thing we're pulling out :3
anonymous
  • anonymous
Lol so we just get 5x-3 (:
zepdrix
  • zepdrix
\[\large\rm \left[5x\color{orangered}{(x-1)}-3\color{orangered}{(x-1)}\right]\quad=\quad\color{orangered}{(x-1)}\left[5x-3\right]\]Well we can't forget about the factor we pulled out, ya? But yes, we end up with only 5x-3 in the square brackets.
zepdrix
  • zepdrix
You don't have to use square brackets if you don't want :P That was just help explain the process. So our final result from factoring is:\[\large\rm 5x^2-8x+3\quad=\quad (x-1)(5x-3)\]
zepdrix
  • zepdrix
Did the factoring from the square brackets step make sense? :o I know that one can be a little tricky.
anonymous
  • anonymous
Ohhh my bad lol i just wasnt thinking, for some reason I thought the (x-1) just canceled out.. Lol so let me see if I can simplify now
anonymous
  • anonymous
Yayyyy! I solved it (: I got 4/x-11 thank you bunches
zepdrix
  • zepdrix
yay \c:/

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