marigirl
  • marigirl
Please help me form a quadratic equation
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
marigirl
  • marigirl
|dw:1440828489889:dw|
marigirl
  • marigirl
\[y=a (\frac{ b }{ 2 }+x)(\frac{ b }{ 2}-x)\] Is that a good start?
ganeshie8
  • ganeshie8
Looks good, plugin the point \((0, h)\) and find the value of \(a\)

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marigirl
  • marigirl
-a
ganeshie8
  • ganeshie8
what do you mean?
marigirl
  • marigirl
y= -a (b/2+x) (b/2-x) Or y= a (b/2+x) (b/2-x) Should I do -a or a I should do -a because it's a negative quadratic
ganeshie8
  • ganeshie8
It doesn't matter
ganeshie8
  • ganeshie8
\[y=a (\frac{ b }{ 2 }+x)(\frac{ b }{ 2}-x)\] plugin the point \((0, h)\) and find the value of \(a\)
marigirl
  • marigirl
Ok I got a= 4h/b^2 Shouldn't be a negative value?
ganeshie8
  • ganeshie8
so the equation is \[y=\dfrac{4h}{b^2} (\frac{ b }{ 2 }+x)(\frac{ b }{ 2}-x)\] simplify if you want to
Elise_a18
  • Elise_a18
dang. I learned this last year and already forget how
marigirl
  • marigirl
Ahhhhhhhhh yes y=(-4h-x^2/b^2)+h
ganeshie8
  • ganeshie8
do you mean y = -(4h/b^2)x^2+h ?
Elise_a18
  • Elise_a18
can you help me with my geometry? ;~;
marigirl
  • marigirl
Wait I stuffed up
Elise_a18
  • Elise_a18
im really sorry
marigirl
  • marigirl
I expanded the bracket and simplified to y= h - (4hx^2/b^2)
marigirl
  • marigirl
Thanks!

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