Please help me form a quadratic equation

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Please help me form a quadratic equation

Mathematics
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\[y=a (\frac{ b }{ 2 }+x)(\frac{ b }{ 2}-x)\] Is that a good start?
Looks good, plugin the point \((0, h)\) and find the value of \(a\)

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Other answers:

-a
what do you mean?
y= -a (b/2+x) (b/2-x) Or y= a (b/2+x) (b/2-x) Should I do -a or a I should do -a because it's a negative quadratic
It doesn't matter
\[y=a (\frac{ b }{ 2 }+x)(\frac{ b }{ 2}-x)\] plugin the point \((0, h)\) and find the value of \(a\)
Ok I got a= 4h/b^2 Shouldn't be a negative value?
so the equation is \[y=\dfrac{4h}{b^2} (\frac{ b }{ 2 }+x)(\frac{ b }{ 2}-x)\] simplify if you want to
dang. I learned this last year and already forget how
Ahhhhhhhhh yes y=(-4h-x^2/b^2)+h
do you mean y = -(4h/b^2)x^2+h ?
can you help me with my geometry? ;~;
Wait I stuffed up
im really sorry
I expanded the bracket and simplified to y= h - (4hx^2/b^2)
Thanks!

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