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|dw:1440836698456:dw|

I tried doing it on my own and got this:\[\frac{360}{\sqrt{3}}ft^{2}\]

I feel like that's wrong somehow...

Alright, let's check.

You split the area into 3 separate sections, yes? The triangle faces and the rectangular sides?

Yes.

And then added the base?

The base is the same as the sides in area, right? :o

|dw:1440837218920:dw|

we need to find x first, and then double it to find the area of the front facing triangluar portion.

I think if I did anything wrong I probably messed up there

I havent worked it out yet so one minute! :P

|dw:1440837311425:dw|
Okay lol

|dw:1440837440575:dw|
Do these look right to you?

Yes

Before the plus: Triangles.
After the plus: Rectangles

Arg... latex!

LOL
Brb I have a mosquito in my house. -_-

I used 3 instead of 2 for red because I just stuck all the rectangular areas together.

yeah that works too.

I mean is it good so far* (what is wrong with my grammar)

\[SA = \frac{288}{\sqrt{3}} +\frac{72}{\sqrt{3}}\]

Then simplify it some more, and you get \[SA= \frac{360\sqrt{3}}{3} = 120\sqrt{3}\]

Yes. I did get that...
But what's up with the other one giving me\[\frac{240}{\sqrt{3}}\]

I did redo it with my own numerical values from my problem, but I still got a different answer.

OK let me work it out first, one min.

Sorry if im a ltitle slow in my responses right now, Kind of getting drowsy.

*It wasn't 240/root 3

Yeah I think it was too long-winded and complex as well xD

Okay, now you just solve it with \(a=5\) instead of \(a=6\)

But thank you :D

What o-o

So what I would do is... |dw:1440840514569:dw|

I think I did that subconsciously xD

I got 6/sqrt 3 then x2 = 12/sqrt3

\[\tan(60) = \frac{5}{x} \iff x = \frac{5}{\tan(60)}\]\[y=2\left(\frac{5}{\tan(60)}\right)\]

YEah, then you're good. no need for a long fancy explanation like that guy did.

What is the weird arrow you put there lol
Is there a latex code?

That means its related. I could write either or interchangeably.

`\[\iff\]`

Oh. Is there a latex code x_x?|dw:1440840784961:dw|

Alright so far? (got the code thanks)

Yep, you gt it.

Thank you! :D
I can handle it from here. Sorry to make you stay up to help me ^^;

No its fine :)

Good luck~