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JozelynW
 one year ago
What makes this equation 6√x+3 +1=30 extraneous apart from this one? (2√X+10 +3=23)
JozelynW
 one year ago
What makes this equation 6√x+3 +1=30 extraneous apart from this one? (2√X+10 +3=23)

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JozelynW
 one year ago
Best ResponseYou've already chosen the best response.0@ganeshie8 can you help me pleaseeeee.

JozelynW
 one year ago
Best ResponseYou've already chosen the best response.0I know it has something to do with the negative index

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Is a negative index possible? Are you saying the problem is this? \[\sqrt[6]{x+3}+1=30\]

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1its because of the negative 6 in the first equation we get sqrt(x + 3) = 29/6 squaring gives x + 3 = (29/6)^2

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1in the second equation the right side is positive ans a genuine solution is obtained

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@welshfella That's how I read it at first, but then they mentioned a negative index and completely threw me. Your interpretation is the only one that makes sense

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1the important thing to remember is that there are 2 square roots a positive and a negative. So squaring both gives the same value.

JozelynW
 one year ago
Best ResponseYou've already chosen the best response.0I thought the the 6 was called the index that's why I said "I know it has something to do with the negative index". Sorry ,anyway what would the 6 be called then?

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1you could call a coefficient

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1like 8x: 8 is the coefficient of x

JozelynW
 one year ago
Best ResponseYou've already chosen the best response.0So, the negative number makes the equation extraneous . But y?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[6\sqrt{x+3}+1=30\] \[6\sqrt{x+3}=29\] \[\sqrt{x+3}=\frac{ 29 }{ 6 }\] The next step would be to square both sides, but the square root of a real number can't be negative. So whatever result you get by solving the equation won't be an actual solution.
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