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JozelynW

  • one year ago

What makes this equation -6√x+3 +1=30 extraneous apart from this one? (2√X+10 +3=23)

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  1. JozelynW
    • one year ago
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    @ganeshie8 can you help me pleaseeeee.

  2. JozelynW
    • one year ago
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    I know it has something to do with the negative index

  3. anonymous
    • one year ago
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    Is a negative index possible? Are you saying the problem is this? \[\sqrt[-6]{x+3}+1=30\]

  4. welshfella
    • one year ago
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    its because of the negative 6 in the first equation we get sqrt(x + 3) = 29/-6 squaring gives x + 3 = (29/-6)^2

  5. welshfella
    • one year ago
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    in the second equation the right side is positive ans a genuine solution is obtained

  6. anonymous
    • one year ago
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    @welshfella That's how I read it at first, but then they mentioned a negative index and completely threw me. Your interpretation is the only one that makes sense

  7. welshfella
    • one year ago
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    the important thing to remember is that there are 2 square roots a positive and a negative. So squaring both gives the same value.

  8. JozelynW
    • one year ago
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    I thought the the -6 was called the index that's why I said "I know it has something to do with the negative index". Sorry ,anyway what would the -6 be called then?

  9. welshfella
    • one year ago
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    you could call a coefficient

  10. welshfella
    • one year ago
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    like 8x:- 8 is the coefficient of x

  11. JozelynW
    • one year ago
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    ok

  12. JozelynW
    • one year ago
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    So, the negative number makes the equation extraneous . But y?

  13. anonymous
    • one year ago
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    \[-6\sqrt{x+3}+1=30\] \[-6\sqrt{x+3}=29\] \[\sqrt{x+3}=-\frac{ 29 }{ 6 }\] The next step would be to square both sides, but the square root of a real number can't be negative. So whatever result you get by solving the equation won't be an actual solution.

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