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anonymous

  • one year ago

HELP please :) A patient requires an IV of 0.9% saline solution, also known as normal saline solution. How much distilled water, to the nearest milliliter, must be added to 100 milliliters of a 6 % saline solution to produce normal saline?

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  1. anonymous
    • one year ago
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    :)

  2. madhu.mukherjee.946
    • one year ago
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    :)

  3. anonymous
    • one year ago
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    :(

  4. madhu.mukherjee.946
    • one year ago
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    @Rushwr @ganeshie8

  5. madhu.mukherjee.946
    • one year ago
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    wait @TRICIACOLLIN i'm trying to help u

  6. anonymous
    • one year ago
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    Thanks... :))) go on. i thought i was snobbed. hihi

  7. madhu.mukherjee.946
    • one year ago
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    @Abhisar @aaronq

  8. madhu.mukherjee.946
    • one year ago
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    @chmvijay

  9. Abhisar
    • one year ago
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    x % of a saline solution means that x grams of salts are dissolved in 100 ml of water.

  10. madhu.mukherjee.946
    • one year ago
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    okay but pls solve this problem

  11. Abhisar
    • one year ago
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    Do you know the answer?

  12. anonymous
    • one year ago
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    sadly no :(

  13. Abhisar
    • one year ago
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    Ok, no probs...just wanted to check.

  14. Abhisar
    • one year ago
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    We can use, Initial volume \(\times\) Initial concentration = Final volume \(\times\) Final concentration

  15. madhu.mukherjee.946
    • one year ago
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    then

  16. Abhisar
    • one year ago
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    Consider you need to add x ml of water then you can write \(\sf 0.06\times 100=0.009 \times (100+x)\) Solve for x

  17. Abhisar
    • one year ago
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    I'll suggest you to cross check it cz my physical chem is rusted ...

  18. madhu.mukherjee.946
    • one year ago
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    is the answer 566.67 ml

  19. anonymous
    • one year ago
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    yes.. thank you! :)))) to both of you :)))

  20. anonymous
    • one year ago
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    A quadratic equation with real coefficients and leading coefficient 1, has x = -bi as a root. Write the equation in general form. :))

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