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anonymous
 one year ago
Solve the following system of equations y = −x2 + 4 y = 2x + 1
Can someone help me with this one? I got no answer but I think it's wrong
anonymous
 one year ago
Solve the following system of equations y = −x2 + 4 y = 2x + 1 Can someone help me with this one? I got no answer but I think it's wrong

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Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.0x^2 + 4 = 2x + 1 x^2  2x + 3 = 0 factor

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0would it be x = 1 or x = 3 ?

Abhisar
 one year ago
Best ResponseYou've already chosen the best response.0Do you mean there are two equations \(\sf y = −x2 + 4~and~y = 2x + 1\) ?

Abhisar
 one year ago
Best ResponseYou've already chosen the best response.0You can subtract second equation from first one to get a quadratic equation in terms of x only and then solve it to find the value of x. Finally substitute this value of x in any of the parent equation to find the value of y

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So x^2 +4 = 2x + 1 and I still get x=1 or 3

Abhisar
 one year ago
Best ResponseYou've already chosen the best response.0So that gives you a quadratic equation \(\sf x=\Large \frac{2 \pm \sqrt{2^2(4 \times1 \times 3)}}{2}\)
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