anonymous
  • anonymous
(5x^3 -x^2+8x -55)/(x^4 +5x^3+11x^2) decompose into partial functions...please help?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
dinamix
  • dinamix
(5x^3-x^2+8x-55)/x(x^3+5x^2+11x) @hailbug i help u bit
anonymous
  • anonymous
would I only be factoring one x from the denominator or x^2?
dinamix
  • dinamix
no thats only u have thing little dude

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
what? sorry I'm confused
anonymous
  • anonymous
@hailbug why do need to decompose into partial functions?
anonymous
  • anonymous
its part of my summer calc homework. i've searched every tutorial for this but I literally can't find anything that closely resembles this. I was hoping someone would help me out
dinamix
  • dinamix
@hailbug u have use Euclidean division thats only
anonymous
  • anonymous
@hailbug do need solution or answer?
anonymous
  • anonymous
@ASAAD123 solution
anonymous
  • anonymous
you need to start by factoring the whole denominator. The common denominator is x², so it's \[\frac{ 5x^3-x^2+8x-55 }{ x^2(x^2+5x+11) }\] Both of those are quadratic so you can use\(\frac{ Ax+B }{ ax^2+bx+c }\) as a guess. \[\frac{ 5x^3-x^2+8x-55 }{ x^2(x^2+5x+11) }=\frac{ Ax+B }{ x^2 }+\frac{ Cx+D }{ x^2+5x+11 }\]
dinamix
  • dinamix
@peachpi yes this is the anwer
anonymous
  • anonymous
for a full table http://tutorial.math.lamar.edu/Classes/CalcII/PartialFractions.aspx
anonymous
  • anonymous
It's not the answer, just a guess at the format. You still have to multiply, solve the system, etc to get the coefficients
anonymous
  • anonymous
thank you so much that makes so much sense. I was trying to factor everything thinking that was the answer
dinamix
  • dinamix
i want ask u qustion how did u know degree of Numerator is Ax+B and cx+D not only D or ax^2 +cx+d ? @peachpi
freckles
  • freckles
the numerator should be at least one degree less than the denominator @dinamix
dinamix
  • dinamix
cuz i like your method but i use only (euclidean division ) i want learn other method @peachpi @freckles
freckles
  • freckles
So if the denominator is 2nd degree, then new numerator choice should be something like Ax+B since this will also include B since A can be zero still (which means the degree of the numerator will be either 0 or 1).
dinamix
  • dinamix
@freckles ty so much
anonymous
  • anonymous
anonymous
  • anonymous
@peachpi so I got the answer \[((3x - 5)/x^2)+ ((2x-11)/x^2 +5x +11) \] is this correct?
anonymous
  • anonymous
oh haha @ASAAD123 didn't see that, sorry
anonymous
  • anonymous
\[\frac{ -5 }{ x^2 }+\frac{ 3 }{ x }+\frac{ 2x-11 }{ x^2+5x+11 }\]
anonymous
  • anonymous
@hailbug correct
dinamix
  • dinamix
denominator is degree 4 not 5 @ASAAD123
dinamix
  • dinamix
u make mistake
anonymous
  • anonymous
@dinamix where is that mistake?
anonymous
  • anonymous
yes that's correct @ASAAD123
dinamix
  • dinamix
its ax+d/x^2 + bx+c/x^2+5x+11
anonymous
  • anonymous
the denominator is still degree 4. You can split that first one up and then the denominator will reduce to x. |dw:1440868401732:dw|
dinamix
  • dinamix
hmm ok
anonymous
  • anonymous
basically, you need to look at the degree of the least common denominator, not the sum of the individual degrees
dinamix
  • dinamix
ok i understand know , ty

Looking for something else?

Not the answer you are looking for? Search for more explanations.