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anonymous
 one year ago
A carpenter builds a solid wood door with dimensions 1.95 m × 0.91 m × 6.0 cm . Its thermal conductivity is k=0.120W/(m⋅K). The air films on the inner and outer surfaces of the door have the same combined thermal resistance as an additional 1.9 cm thickness of solid wood. The inside air temperature is 23.0 ∘C , and the outside air temperature is 5.00 ∘C .
anonymous
 one year ago
A carpenter builds a solid wood door with dimensions 1.95 m × 0.91 m × 6.0 cm . Its thermal conductivity is k=0.120W/(m⋅K). The air films on the inner and outer surfaces of the door have the same combined thermal resistance as an additional 1.9 cm thickness of solid wood. The inside air temperature is 23.0 ∘C , and the outside air temperature is 5.00 ∘C .

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What is the rate of heat flow through the door? Express your answer using two significant figures.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what's the specific heat capacity of the material in question?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I just noted your k value I missed it.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Alrigth you are aware that measurement of temperature is in Kalvin scale.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Think of the heat transfer from inside the door to the surface door as an act of thermal equilibrium. All the objects in contact with different temperatures try to reach equilibrium.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0First of all you need to calculate the surface of the door and volume of the door.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0And set everything to meters rather than centimeters because k value is expressed with meters/ Are you reading this? You seem unresponsive.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0This is a problem on how different objects in contact with different temperatures come to thermal equilibrium depending on the surface as well as the volume. Note that it all depends on the potential thermal energy at play.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You can use Fourier's law \[Q=\frac{ kA }{ t }(T_{high}T_{low})\] Q = heat rate k = thermal conductivity A = crosssectional area of the surface perpendicular to the flow. Looks like that's 1.95 m by 6.0 m t = thickness of the surface. In this case you'd have to add an extra 1.9 cm to the 0.91 m to get the total thickness of the door

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0check your units. Make sure all the lengths are in meters

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Q = (0.12 W/mK)(1.95 m)(6.0 m)(23 °C  (5 °C))/(0.91 m + 0.019 m)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i pluged it in still wrong
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