MEDAL. Check answer PLEASE

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MEDAL. Check answer PLEASE

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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x-intercepts when graph of the equation intersects x-axis when y = 0 so substitute y for 0 solve for x to find x-intercepts y-intercepts when graph of the equation intersects y-axis x=0 substitute x for 0 to find y-intercept
That's what I did. I'm just asking if I got it correct.

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ok y intercept is correct :) but u shuld recheck ur calculations for x intercept :)
how did you get 1/4 ??
I completed the square and solved for x. |dw:1440867471404:dw| |dw:1440867517518:dw| |dw:1440867556021:dw|
|dw:1440867708260:dw|
i don't understand what u did there |dw:1440867656693:dw| h
I divided by 8
just 2 ? you should keep the 2 to the right side and then divide by 8
and remember it's x^2
???
\[(x-1/8)^2 = x^2 + 1/64 - 2(x)(1/8)\]|dw:1440867959965:dw|
that is the part where u made a mistake ^
Oh, oops.
I see now.
:)
|dw:1440868080232:dw|
OR \[\huge\rm 8x^2=2\] divide by 8 and then take square root it would be easy complete the square isn't required
yes correct :)
Thanks. :) I guess I totally overhtought it.
hehe :)
Thank you both @ytrewqmiswi @Nnesha
no prblem :)
my pleasure
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