1. StudyGurl14

2. Nnesha

x-intercepts when graph of the equation intersects x-axis when y = 0 so substitute y for 0 solve for x to find x-intercepts y-intercepts when graph of the equation intersects y-axis x=0 substitute x for 0 to find y-intercept

3. StudyGurl14

That's what I did. I'm just asking if I got it correct.

4. ytrewqmiswi

ok y intercept is correct :) but u shuld recheck ur calculations for x intercept :)

5. Nnesha

how did you get 1/4 ??

6. StudyGurl14

I completed the square and solved for x. |dw:1440867471404:dw| |dw:1440867517518:dw| |dw:1440867556021:dw|

7. StudyGurl14

|dw:1440867708260:dw|

8. Nnesha

i don't understand what u did there |dw:1440867656693:dw| h

9. StudyGurl14

I divided by 8

10. Nnesha

just 2 ? you should keep the 2 to the right side and then divide by 8

11. Nnesha

and remember it's x^2

12. StudyGurl14

???

13. ytrewqmiswi

$(x-1/8)^2 = x^2 + 1/64 - 2(x)(1/8)$|dw:1440867959965:dw|

14. ytrewqmiswi

that is the part where u made a mistake ^

15. StudyGurl14

Oh, oops.

16. StudyGurl14

I see now.

17. ytrewqmiswi

:)

18. StudyGurl14

|dw:1440868080232:dw|

19. Nnesha

OR $\huge\rm 8x^2=2$ divide by 8 and then take square root it would be easy complete the square isn't required

20. ytrewqmiswi

yes correct :)

21. StudyGurl14

Thanks. :) I guess I totally overhtought it.

22. ytrewqmiswi

hehe :)

23. StudyGurl14

Thank you both @ytrewqmiswi @Nnesha

24. ytrewqmiswi

no prblem :)

25. Nnesha

my pleasure

26. anonymous

DO YOU STILL NEED HELP OR WHAT?