For the reaction 2 H2 (g) + O2 (g) → 2 H2O (g) it was found that at a given temperature and after a certain time the rate of formation of H2O(g) was 0.27 mol L-1 s-1. What is the rate of consumption of H2 (g) in mol L-1 s-1?

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For the reaction 2 H2 (g) + O2 (g) → 2 H2O (g) it was found that at a given temperature and after a certain time the rate of formation of H2O(g) was 0.27 mol L-1 s-1. What is the rate of consumption of H2 (g) in mol L-1 s-1?

Chemistry
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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is 0.27 mol L-1 s-1 |dw:1440875638422:dw|

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Other answers:

?????? what does that even say?
Now imma take a wild guess and say since 2 moles of h20 are being made per every 2 moles of H2 then the rates must be the same. Wild educated guess.
so 0.27 mol L-1 s-1
My book confirms it
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it should be a negative rate because it's being consumed

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