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happykiddo
 one year ago
The speed of a wave pulse on a string depends on the tension, F, in the string and the mass per unit length, μ, of the string. Tension has SI units of kg.m.s2 and the mass per unit length has SI units of kg.m1 What combination of F and μ must the speed of the wave be proportional to?
happykiddo
 one year ago
The speed of a wave pulse on a string depends on the tension, F, in the string and the mass per unit length, μ, of the string. Tension has SI units of kg.m.s2 and the mass per unit length has SI units of kg.m1 What combination of F and μ must the speed of the wave be proportional to?

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happykiddo
 one year ago
Best ResponseYou've already chosen the best response.0answer is( F / μ) i just don't know why

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what's u stand for in that regard?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0coefficient for what

happykiddo
 one year ago
Best ResponseYou've already chosen the best response.0its the symbol for Mu

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I don't know what that means

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Hey without you telling me the background info of the question I cannot hel you

happykiddo
 one year ago
Best ResponseYou've already chosen the best response.0sorry my computer battery turned off, Mu is mass/length string

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Basically the mas each unit of length consists of.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok tenser the line greater the velocity at which the wave transfers from position A to position B is that what you are not quite on the spot

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Greater the mass of the line per unit of length harder it is for the pulse to traverse because it takes greater energy to move greater mass to transfer the pulse.

happykiddo
 one year ago
Best ResponseYou've already chosen the best response.0Thank you for the help : )

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but you still get the idea.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0this is a dimensional analysis problem. You actually have to write out the dimensions to figure out the equation. You're trying to combine the units of T and µ to give m/s, the unit of speed. Both T and µ have units of kg, but speed doesn't, so you know it they must be divided so the kg will cancel. \[\frac{ [T] }{ [\mu] }=\frac{ \frac{ kgm }{ s^2 } }{ \frac{ kg }{ m } }=\frac{ m^2 }{ s^2 }\] The unit you want is m/s, so you have to take the square root. \[[v]=\sqrt{\frac{ m^2 }{ s^2 }}=\frac{ m }{ s }\] \[v \propto \sqrt{\frac{ T }{ \mu }}\]
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