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happykiddo

  • one year ago

The speed of a wave pulse on a string depends on the tension, F, in the string and the mass per unit length, μ, of the string. Tension has SI units of kg.m.s-2 and the mass per unit length has SI units of kg.m-1 What combination of F and μ must the speed of the wave be proportional to?

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  1. happykiddo
    • one year ago
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    answer is( F / μ) i just don't know why

  2. anonymous
    • one year ago
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    what's u stand for in that regard?

  3. anonymous
    • one year ago
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    coefficient for what

  4. happykiddo
    • one year ago
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    its the symbol for Mu

  5. anonymous
    • one year ago
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    I don't know what that means

  6. anonymous
    • one year ago
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    so tell me

  7. anonymous
    • one year ago
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    Hey without you telling me the background info of the question I cannot hel you

  8. happykiddo
    • one year ago
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    sorry my computer battery turned off, Mu is mass/length string

  9. anonymous
    • one year ago
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    Basically the mas each unit of length consists of.

  10. anonymous
    • one year ago
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    Ok tenser the line greater the velocity at which the wave transfers from position A to position B is that what you are not quite on the spot

  11. anonymous
    • one year ago
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    Greater the mass of the line per unit of length harder it is for the pulse to traverse because it takes greater energy to move greater mass to transfer the pulse.

  12. happykiddo
    • one year ago
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    Thank you for the help : )

  13. happykiddo
    • one year ago
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    F/u was incorrect

  14. happykiddo
    • one year ago
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    its sqrt(T/u)

  15. anonymous
    • one year ago
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    but you still get the idea.

  16. anonymous
    • one year ago
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    this is a dimensional analysis problem. You actually have to write out the dimensions to figure out the equation. You're trying to combine the units of T and µ to give m/s, the unit of speed. Both T and µ have units of kg, but speed doesn't, so you know it they must be divided so the kg will cancel. \[\frac{ [T] }{ [\mu] }=\frac{ \frac{ kg-m }{ s^2 } }{ \frac{ kg }{ m } }=\frac{ m^2 }{ s^2 }\] The unit you want is m/s, so you have to take the square root. \[[v]=\sqrt{\frac{ m^2 }{ s^2 }}=\frac{ m }{ s }\] \[v \propto \sqrt{\frac{ T }{ \mu }}\]

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