Loser66
  • Loser66
Conjecture the formula for the nth term of {a_n} if the first ten terms of it is 1,0,0,1,0,0,0,0,1,0 Please, help
Mathematics
katieb
  • katieb
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

Loser66
  • Loser66
I want to use the floor function to put it in neat. Obviously, |dw:1440875326682:dw|
Loser66
  • Loser66
But how?
freckles
  • freckles
what do you mean how if you say it is obvious?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

freckles
  • freckles
is the piecewise part obvious but not how to write in the floor format? is that what you?
freckles
  • freckles
is that what you mean*?
ikram002p
  • ikram002p
oh that remind me of Legendre function
Loser66
  • Loser66
When I say "obvious" , it means we can see it obviously.
freckles
  • freckles
ok then what do you need help on then
Loser66
  • Loser66
I want the floor format.
freckles
  • freckles
oh okay
Loser66
  • Loser66
\(\lfloor{\sqrt n}\rfloor\)
Loser66
  • Loser66
How about this? \(1<\sqrt 2 < 2\), hence \(\lfloor{\sqrt 2}\rfloor =1\) and \(\lfloor{\dfrac{\lfloor{\sqrt 2}\rfloor}{\sqrt2}}\rfloor=0\)
Loser66
  • Loser66
It works well for n =3,4, 5, 6... but how can I just list them out like this? I want a general logic to lead me there.
ikram002p
  • ikram002p
so sqrt(n^2) is integer, then [sqrt(n^2) ] would be same integer n else u would have an additional decimals there are two lovely things about floor function 1-[sqrt(n^2) ]<= sqrt(n^2) 2-[r]=0 if 0
ikram002p
  • ikram002p
and you can use n =i^2 instead n^2 as the general term lol
Loser66
  • Loser66
Hey, friend , I don't get why \(\sqrt n^2 \). Is it not that it is always = n and n >0 since it is the order of the term.
Loser66
  • Loser66
If we consider \(\lfloor{\sqrt n^2}\rfloor = \lfloor{n}\rfloor\) and it is = n itself.
Loser66
  • Loser66
since \(n\in \mathbb N\)
ikram002p
  • ikram002p
yes u are correct , its just a variable :D sorry to confuse u ;)
ikram002p
  • ikram002p
i just used it to explain but since u were asked to make general form of n then use n without n^2
Loser66
  • Loser66
oh, I got you. Thank you so much.
ikram002p
  • ikram002p
you are the most wlc <3

Looking for something else?

Not the answer you are looking for? Search for more explanations.