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anonymous
 one year ago
solve the inequality?
x^2e^xlnx>0
anonymous
 one year ago
solve the inequality? x^2e^xlnx>0

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freckles
 one year ago
Best ResponseYou've already chosen the best response.4you only need to solve ln(x)>0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0isn't x undefined then?

freckles
 one year ago
Best ResponseYou've already chosen the best response.4no... \[\ln(x)=y \implies e^{y}=x \\ \text{ here we have } y=0 \\ \text{ so we have } e^{0}=x\] so how do you solve the equation ln(x)=0

freckles
 one year ago
Best ResponseYou've already chosen the best response.4like what is the solution

freckles
 one year ago
Best ResponseYou've already chosen the best response.4and remember y=ln(x) looks like this: dw:1440878660198:dw

freckles
 one year ago
Best ResponseYou've already chosen the best response.4drawing got cut off but that line is suppose to be y=0

freckles
 one year ago
Best ResponseYou've already chosen the best response.4x^2e^xln(x)>0 when x>1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so in interval notation, is it \[(1,\infty)\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.4do you understand how we got that though ?

freckles
 one year ago
Best ResponseYou've already chosen the best response.4dw:1440878804304:dw

freckles
 one year ago
Best ResponseYou've already chosen the best response.4e^x was always positive x^2 was always positive ln(x) was going to determine whether or not e^x*x^2*ln(x) was positive or not

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah, I'm actually kind of mad at myself that I didnt change it to exponential notation.

freckles
 one year ago
Best ResponseYou've already chosen the best response.4just for fun x^2e^xln(x)<0 has solution (0,1)

freckles
 one year ago
Best ResponseYou've already chosen the best response.4I didn't include anything to the left of 0 because ln(x) is undefined there

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0dw:1440879090764:dw your graph for function is like that so f(x)>0 in ] 1; +infinity [ @hailbug
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