anonymous
  • anonymous
Rectangle J'K'L'M' shown on the grid is the image of rectangle JKLM after transformation. The same transformation will be applied on trapezoid STUV, as shown below: What will be the location of U' in the image trapezoid S'T'U'V'? A. (16, −2) B. (14, −2) C. (14, 1) D. (16, 1)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
anonymous
  • anonymous
@calculusxy @phi @peachpi
phi
  • phi
pick a point on rectangle JKLM, say point J which is at (-5,1) where is point J' ?

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anonymous
  • anonymous
In my opinion is A, but im not sure i just need an explanation
phi
  • phi
say point J which is at (-5,1) where is point J' ? can you find point J' and "read off" its (x,y) coordinates?
anonymous
  • anonymous
Point J is at 4,5
phi
  • phi
point J prime J' yes, it is at x=4 what is its y ? (its y is not 5)
anonymous
  • anonymous
y is at 3? im not sure about y
phi
  • phi
how many "steps up" (or boxes) from the x-axis up to J' ?
anonymous
  • anonymous
3?
phi
  • phi
Here is a picture counting up 2 steps (see the red numbers?)
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anonymous
  • anonymous
ohhh, yes i see them
phi
  • phi
so how far up to J' ?
anonymous
  • anonymous
2
phi
  • phi
how far up from the x-axis? (2 gets us 1/2 way)
anonymous
  • anonymous
3 then, i really dont know omg
phi
  • phi
you will get it. you put your finger on the x-axis below J' and count up 1,2,etc until you are at J' (the corner of the rectangle)
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anonymous
  • anonymous
5
phi
  • phi
like this
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anonymous
  • anonymous
ohhh i get it now
phi
  • phi
the corner of the box (labeled J') is at (4,4) from the "origin" you move sideways 4 steps, then 4 steps straight up.
phi
  • phi
so J at (-5,1) moved to J' at (4,4) what do we add to -5 to make it 4 ? what do we add to 1 to make it 4 ?
anonymous
  • anonymous
1 and 3
phi
  • phi
ok on the 3 (so remember we add 3 to the y number) but -5+1 = -4 and we want +4
anonymous
  • anonymous
so what do we do? :/
phi
  • phi
the other way to figure it out is put your finger on J and count how many steps to the right until you are directly under J' (it is more than 1 step)
phi
  • phi
when I say point J, I mean the corner of the rectangle labeled J it is at (-5,1)
anonymous
  • anonymous
i dont get it, the part of counthing steps to the right
phi
  • phi
can you put your finger on the corner of the rectangle near the label J ?
anonymous
  • anonymous
yes
phi
  • phi
and move your finger to the right one box, then two boxes, and so on ?
anonymous
  • anonymous
okay i do that up to where?
phi
  • phi
keep doing that (and counting) until you are directly under the corner of the rectangle labeled J'
anonymous
  • anonymous
2?
phi
  • phi
|dw:1440886102612:dw|
phi
  • phi
if you count it right, it should take 5 steps to get to the y-axis. and we still have some more steps to get to be under J
anonymous
  • anonymous
so its more than 5? its not A like i thought it was?
phi
  • phi
this is a complicated problem. we are trying to figure out how much they moved point J to get to J' we see it was "slid over" so many steps. we need to figure out how far. it is the number of steps to take us from -5 to +4
anonymous
  • anonymous
thats complicated
phi
  • phi
yes. do you see that if we are at J and move 2 steps will be here (see pic)
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anonymous
  • anonymous
yes ii see that.
phi
  • phi
we need to count how many steps from J to get to the "red 1" that is under J'
anonymous
  • anonymous
which J i dont get this sorry.
phi
  • phi
from the red circle to the green circle. how many steps?
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anonymous
  • anonymous
9
phi
  • phi
yes. another way to find that is to do 4 - (-5) = 4+5 = 9 but the idea is we ADD 9 to x and ADD 3 to y
anonymous
  • anonymous
i think it was easier counting the boxes lol
phi
  • phi
it is good to learn how to do the subtraction idea. but now we are almost ready to answer the question What will be the location of U' first, can you read off the (x,y) coords of point U ?
anonymous
  • anonymous
6 and im not sure about the y cord
phi
  • phi
we want the coordinates where the red circle is. first , look on the x-axis. what number are we at when we are right above the red circle?
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anonymous
  • anonymous
7
phi
  • phi
in case you did not know, we are interested in the "corners" of the shape (not where the label is ) yes 7 over. now how far down ? (look on the y-axis... what number is straight across to the red circle) (or count down)
anonymous
  • anonymous
2? im confused there
phi
  • phi
it's -2 because we count down (from the x-axis) (+2 would be 2 above the x-axis)
anonymous
  • anonymous
yes, -2 sorry.
phi
  • phi
Does this help?
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anonymous
  • anonymous
that helps!
phi
  • phi
if you put your finger at the "orgin" (where the x-axis and y-axis cross) you count down 2 steps, then 7 steps to the right, and you will be at the red circle.
phi
  • phi
so we figured out that U is at (-2,7) we now use the "rule" (from up above) if we can still remember it! ADD 9 to x and ADD 3 to y to find where U' is can you do that ?
anonymous
  • anonymous
so i add 9 to -2 abd 3 to 7?
phi
  • phi
oops, I confused the x and y. but yes what you said, but with the correct numbers: so we figured out that U is at (7,-2) we now use the "rule" (from up above) if we can still remember it! ADD 9 to x and ADD 3 to y to find where U' is can you do that ?
anonymous
  • anonymous
16 and 1
phi
  • phi
yes. so that is where U' is
phi
  • phi
(16,1)
anonymous
  • anonymous
so the correct answer is D
phi
  • phi
yes
anonymous
  • anonymous
thank you so much!
phi
  • phi
yw

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