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sjg13e
 one year ago
Find Arc Length
sjg13e
 one year ago
Find Arc Length

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sjg13e
 one year ago
Best ResponseYou've already chosen the best response.0hi, i need helping with both parts of this question! i know that delta = s / r (in radians), but i can't seem to understand how to find the angle

sjg13e
 one year ago
Best ResponseYou've already chosen the best response.0i'm also going to assume r = 7.5

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0there is one information just r.

sjg13e
 one year ago
Best ResponseYou've already chosen the best response.0yes, the only known variable is 'r'. but it seems that there's a way to find the numerical value of theta

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0theta is approximately 60 degree

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1you can make an estimate of the angle theta the slope is about 6.6 so find the angle whose tangent is 6.6

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1that is 81 degrees to the nearest degree

phi
 one year ago
Best ResponseYou've already chosen the best response.0yes, I get height 8.4 and 1.33 to the right so 90  arctan(1.33/8.4) = 81

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1from this you can find the arc length s

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1using radius of 7.5

sjg13e
 one year ago
Best ResponseYou've already chosen the best response.0thank you! i'll try to find s

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0@phi i think its 80 cuz i use long method

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0dw:1440889274064:dw @phi check my frw

sjg13e
 one year ago
Best ResponseYou've already chosen the best response.0i figured out s, it's 10.5 (1.396rad * 7.5). thank you all for your help! :)

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1@dinamix what do you mean by the long method?
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