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lexy148

  • one year ago

i need help graphing y=square root x+3 can anyone help.

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  1. LynFran
    • one year ago
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    \[y=\sqrt{(x+3)}\]or \[y=\sqrt{x}+3\]??

  2. LynFran
    • one year ago
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    which 1 is it??

  3. LynFran
    • one year ago
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    |dw:1440898949781:dw|

  4. jdoe0001
    • one year ago
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    @lexy148 so.. .which is it?

  5. dinamix
    • one year ago
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    |dw:1440892863901:dw|

  6. dinamix
    • one year ago
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    @lexy148 this what u want right look my draw

  7. lexy148
    • one year ago
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    yes the second drawing

  8. lexy148
    • one year ago
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    how do you come up with the plotting points

  9. anonymous
    • one year ago
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    \[y=\sqrt{x+3},y^2=x+3\] it is a parabola , y is positive. so taking only upper part.

  10. dinamix
    • one year ago
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    |dw:1440894108443:dw| i hope u undersand my method i give easy method @lexy148

  11. lexy148
    • one year ago
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    i still dont understand how its negative

  12. lexy148
    • one year ago
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    do you have to come up with points to plot

  13. dinamix
    • one year ago
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    cuz f(-3)= ??

  14. lexy148
    • one year ago
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    oh ok

  15. anonymous
    • one year ago
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    when x=-3 y=0 x=-2,y=1 x=1,y=2 x=6,y=3 ...

  16. lexy148
    • one year ago
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    ok thank you

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