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anonymous
 one year ago
The point(5/13,y) in the fourth quadrant corresponds to angle θ on the unit circle.
sec(theta)=?
cot(theta)=?
anonymous
 one year ago
The point(5/13,y) in the fourth quadrant corresponds to angle θ on the unit circle. sec(theta)=? cot(theta)=?

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triciaal
 one year ago
Best ResponseYou've already chosen the best response.1(x,y) = ( rcos theta, rsintheta)

triciaal
 one year ago
Best ResponseYou've already chosen the best response.1dw:1440896696222:dw

triciaal
 one year ago
Best ResponseYou've already chosen the best response.1dw:1440896725267:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I know that sec(theta)=13/5 But I don't know how to find the solution for cot(theta) without the y coordinate.

triciaal
 one year ago
Best ResponseYou've already chosen the best response.1dw:1440896822327:dw

triciaal
 one year ago
Best ResponseYou've already chosen the best response.1pythagorean theorem c^2 = a^2 + b^2 trig r^2 = (rcos theta)^2 + (r sin theta)^2 eqn of circle r^2 = (xh)^2 + (yk)^2 enough hints/ideas ?

triciaal
 one year ago
Best ResponseYou've already chosen the best response.1by the way 3,4,5 and 5,12, 13 are 2 common triplets

triciaal
 one year ago
Best ResponseYou've already chosen the best response.1dw:1440897186900:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes, thank you for your help (:

triciaal
 one year ago
Best ResponseYou've already chosen the best response.1you are welcome. all the best with your studies.
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