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anonymous

  • one year ago

The point(5/13,y) in the fourth quadrant corresponds to angle θ on the unit circle. sec(theta)=? cot(theta)=?

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  1. triciaal
    • one year ago
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    (x,y) = ( rcos theta, rsintheta)

  2. triciaal
    • one year ago
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    |dw:1440896696222:dw|

  3. triciaal
    • one year ago
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    |dw:1440896725267:dw|

  4. anonymous
    • one year ago
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    I know that sec(theta)=13/5 But I don't know how to find the solution for cot(theta) without the y coordinate.

  5. triciaal
    • one year ago
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    |dw:1440896822327:dw|

  6. triciaal
    • one year ago
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    pythagorean theorem c^2 = a^2 + b^2 trig r^2 = (rcos theta)^2 + (r sin theta)^2 eqn of circle r^2 = (x-h)^2 + (y-k)^2 enough hints/ideas ?

  7. triciaal
    • one year ago
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    by the way 3,4,5 and 5,12, 13 are 2 common triplets

  8. triciaal
    • one year ago
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    |dw:1440897186900:dw|

  9. triciaal
    • one year ago
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    all good?

  10. anonymous
    • one year ago
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    Yes, thank you for your help (:

  11. triciaal
    • one year ago
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    you are welcome. all the best with your studies.

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