anonymous
  • anonymous
The point(5/13,y) in the fourth quadrant corresponds to angle θ on the unit circle. sec(theta)=? cot(theta)=?
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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triciaal
  • triciaal
(x,y) = ( rcos theta, rsintheta)
triciaal
  • triciaal
|dw:1440896696222:dw|
triciaal
  • triciaal
|dw:1440896725267:dw|

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anonymous
  • anonymous
I know that sec(theta)=13/5 But I don't know how to find the solution for cot(theta) without the y coordinate.
triciaal
  • triciaal
|dw:1440896822327:dw|
triciaal
  • triciaal
pythagorean theorem c^2 = a^2 + b^2 trig r^2 = (rcos theta)^2 + (r sin theta)^2 eqn of circle r^2 = (x-h)^2 + (y-k)^2 enough hints/ideas ?
triciaal
  • triciaal
by the way 3,4,5 and 5,12, 13 are 2 common triplets
triciaal
  • triciaal
|dw:1440897186900:dw|
triciaal
  • triciaal
all good?
anonymous
  • anonymous
Yes, thank you for your help (:
triciaal
  • triciaal
you are welcome. all the best with your studies.

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