The point(5/13,y) in the fourth quadrant corresponds to angle θ on the unit circle. sec(theta)=? cot(theta)=?

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The point(5/13,y) in the fourth quadrant corresponds to angle θ on the unit circle. sec(theta)=? cot(theta)=?

Algebra
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(x,y) = ( rcos theta, rsintheta)
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Other answers:

I know that sec(theta)=13/5 But I don't know how to find the solution for cot(theta) without the y coordinate.
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pythagorean theorem c^2 = a^2 + b^2 trig r^2 = (rcos theta)^2 + (r sin theta)^2 eqn of circle r^2 = (x-h)^2 + (y-k)^2 enough hints/ideas ?
by the way 3,4,5 and 5,12, 13 are 2 common triplets
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all good?
Yes, thank you for your help (:
you are welcome. all the best with your studies.

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