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anonymous
 one year ago
Simplify:
anonymous
 one year ago
Simplify:

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1440898252857:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[(4x^2)(1/3)(6x+1)^{2/3}(6)(6x+1)^{1/3}(2x) / (4x^2)^2\]

LynFran
 one year ago
Best ResponseYou've already chosen the best response.26*1/3=2 ...\[\frac{[2( 4x ^{2})(6x+1)^{\frac{ 2 }{ 3 }}][(6x+1)^{\frac{ 1 }{ 3 }}(2x)] }{ (4x ^{2})^{2} }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do you start canceling?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I have the answer, and that isn't right. I need to know how to work it.

LynFran
 one year ago
Best ResponseYou've already chosen the best response.2\[\frac{ 2(6x+1)^{1/3} [(6x+1)^{1/3}(4x ^{2})(x)]}{ (4x ^{2})^{2} }\]

LynFran
 one year ago
Best ResponseYou've already chosen the best response.2@Loser66 what do u think..

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.01/3 is an exponent at the numerator ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0\[\large\rm \frac{ 6 (4x^2)^\frac{ 1 }{ 3 } (6x+1)^\frac{ 2 }{ 3}(6x+1)^\frac{ 1 }{ 3 }(2x) }{ (4x^2)^2}\]hmm like this ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0There is no 1/3 exponent for (4x^2).

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[(4x^2)(1/3)(6x+1)^{2/3}(6x+1)^{1/3}(2x) / (4x^2)^2\] is the problem

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0\[\large\rm \frac{ 6(\frac{1}{3}) (4x^2) (6x+1)^\frac{ 2 }{ 3}(6x+1)^\frac{ 1 }{ 3 }(2x) }{ (4x^2)^2}\] looks right ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0no hmm can you please take a screenshot

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0\(\color{blue}{\text{Originally Posted by}}\) @ducksonquack \[(4x^2)(1/3)(6x+1)^{2/3}(6)(6x+1)^{1/3}(2x) / (4x^2)^2\] \(\color{blue}{\text{End of Quote}}\) there is 6

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0\(\color{blue}{\text{Originally Posted by}}\) @ducksonquack I have the answer, and that isn't right. I need to know how to work it. \(\color{blue}{\text{End of Quote}}\) what's the answer jsut want to check if i'm doing this right or not>.<

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[2(5x^2+x+4) / (4x^2)^2(6x+?)^{2/3}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Didn't catch what the ? mark was when we were given the answers.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well that's in your problem, it states \((6x+1)\) in parenthesis.... so im sure the \(? = 1\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0One second im solving it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Alright got it, so...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[=\frac{\frac{1}{3}\cdot 6 \cdot (4x^2)(6x+1)^{2/3}(6x+1)^{1/3}(2x)}{(4x^2)^2}\]\[=\frac{(6x+1)^{2/3}\left(2\left[4x^2(6x+1)(x)\right]\right)}{(4x^2)^2}\]\[=\frac{2\left[4x^2+6x+x\right]}{(4x^2)^2(6x+1)^{2/3}}\]\[=\boxed{\frac{2(5x^2+x+4)}{(4x^2)^2(6x+1)^{2/3}}}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can you explain it to me step by step?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay so what you want to do first is look for a common like term. in this case it would be \((6x+1)^{2/3}\). Notice how its a common multiplier in the numerator? We can pull it out. Now I pulled out \((6x+1)^{2/3}\) instead of the \((6x+1)^{1/3}\) because outof the two, \((6x+1)^{2/3}\) is the smaller power, therefore pulling it out as a common factor, I am left with \((6x+1)^1\) inside the brackets. (Remember: \((6x+1)^{2/3} \cdot (6x+1)^1 = (6x+1)^{1/3}\)) Now I pulled out a 2 inside the brackets because that is another common like term between the entire function within the brackets. \([2(4x^2)(6x+1)(2x)] \iff 2[(4x^2(6x+1)(x)]\) Then I simplify my fraction even further by turning \((6x+1)^{2/3}\) positive by putting it in the denominator. this turns it positive. Recall that: \(x^{\#} \iff \dfrac{1}{x^{\#}}\) So far we have: \[\frac{2[4x^2(6x+1)(x)]}{(4x^2)^2(6x+1)^{2/3}}\] Now we simplify the stuff inside the brackets without multiplying in the 2. \[\frac{2[4x^2 +6x+x]}{(4x^2)^2(6x+1)^{2/3}}\] Simplify this a bit more and you'll have: \(\boxed{ \dfrac{2[5x^2+x+4]}{(4x^2)^2(6x+1)^{2/3}}}\)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0sorry i was afk great explanation jhanny!
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