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anonymous
 one year ago
find the acute angle between the lines x+2y=7 and 5xy=2
anonymous
 one year ago
find the acute angle between the lines x+2y=7 and 5xy=2

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I did\[\tan^{1} \left( 5 \right)=78.69 degrees\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and \[\tan^{1} \left( .5 \right)=26.75 degrees\] so arent yu supposed to subtract that from 180 to get 153.43 degrees

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0then you subtract 153.43 degrees from 78.69 degrees to get 75.74 degrees?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can anyone tell me if this is correct?

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1440901646597:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is what i did correct? i just need to know if the answer i got is correct

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0I don't know sorry but the intersection is (1,3)

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1440902711014:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.02y=x+7 \[y=\frac{ 1 }{ 2 }x+\frac{ 7 }{ 2 }\] slope\[m _{1}=\frac{ 1 }{ 2 }\] y=5x7 its slope\[m _{2}=5\] let theta be the angle between them. \[\tan \theta =\left \frac{ m _{1}m _{2} }{ 1+m _{1}m _{2} } \right\] \[\tan \theta=\left \frac{ \frac{ 1 }{ 2 }5 }{ 1+\left( \frac{ 1 }{ 2 } \right)*5 } \right\] \[\tan \theta=\left \frac{ \frac{ 11 }{ 2 } }{ 1\frac{ 5 }{ 2 } } \right=\left\frac{ 11 }{ 2 }\times \frac{ 2 }{ 3 } \right\] \[=\frac{ 11 }{ 3 }\] \[\theta=\tan^{1} \left( \frac{ 11 }{ 3 } \right)\] =74.74degree

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0interesting 72, 75, 78 as in 75 +/ 3
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