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anonymous
 one year ago
Sophie drove 225 mi south through the Smoky Mountains. Snow during her return trip made her average speed on the return trip 30 mph slower. The total driving time was 8 hr. Find Sophie’s average sped on each part of the trip.
anonymous
 one year ago
Sophie drove 225 mi south through the Smoky Mountains. Snow during her return trip made her average speed on the return trip 30 mph slower. The total driving time was 8 hr. Find Sophie’s average sped on each part of the trip.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Let r be the speed to the Smoky Mountains. r t = d, t = d/r Solve the following for r:\[\frac{225}{r}+\frac{225}{r30}=8 \]r = 45/4 mph or 75 mph .\[\frac{225}{r}+\frac{225}{r}=8 \]With no delay: r = 56.25 mph The initial speed had to be greater than 56.25 mph when there was a delay. Therefore r has to be 75mph on the trip to the Mountains and 45 mph on the return.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You are a life saver....thank you soooo very much!

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0@robtobey nice job

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you and thank you for medal.

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0your welcome
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