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- anonymous

In the figure, block 1 of mass m1 = 1.8 kg and block 2 of mass m2 = 1.4 kg are connected by a string of negligible mass. Block 2 is pushed by force Upper F Overscript right-arrow EndScripts of magnitude 18 N and angle θ = 34°. The coefficient of kinetic friction between each block and the horizontal surface is 0.16. What is the tension in the string?

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- anonymous

- katieb

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- anonymous

- anonymous

Will try answering this problem in a few hours after school. Just posted here in advance. Thank you for those who are willing to help. God bless mates~!

- IrishBoy123

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- Michele_Laino

here is the situation of your problem:
|dw:1440941027910:dw|
the equation of the motion of both objects, are:
\[\Large \left\{ \begin{gathered}
{\mathbf{F}} + {\mathbf{T}} + {{\mathbf{R}}_2} = {m_2}{\mathbf{a}} \hfill \\
{{\mathbf{R}}_1} + \left( { - {\mathbf{T}}} \right) = {m_1}{\mathbf{a}}\quad \hfill \\
\end{gathered} \right.\]

- Michele_Laino

developing those equation with respect to the coordinate system x,z as in the drawing above, we get:
\[\Large \left\{ \begin{gathered}
F\cos \theta + \left( {F\sin \theta + {m_2}g} \right)\mu - T = {m_2}a \hfill \\
- \mu {m_1}g + T = {m_1}a \hfill \\
\end{gathered} \right.\]
where a is the requested acceleration, and T is the tension of the string between the 2 objects
|dw:1440941667928:dw|

- Michele_Laino

furthermore \mu is the coefficient of friction

- anonymous

hello I'm back sorry forgot to check this problem bc of school worksss. Will read your text thanks @Michele_Laino

- anonymous

is the force with an angle a compression force right? Not a tension

- anonymous

I'll draw a FBD via coordinate system

- anonymous

|dw:1441155866872:dw|

- anonymous

anyone is my FBD right?

- anonymous

I thought in block 1 the equation will be T1 - F ?

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