A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
A student pours 46.8g of water at 17oC into a beaker containing 111.4g or water at 17oC. The density of water at 17oC is 1.00 g/mL.
(a) What is the final mass?
(b) What is the final temperature?
(c) What is the final density?
anonymous
 one year ago
A student pours 46.8g of water at 17oC into a beaker containing 111.4g or water at 17oC. The density of water at 17oC is 1.00 g/mL. (a) What is the final mass? (b) What is the final temperature? (c) What is the final density?

This Question is Closed

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2We can remember that density \(\rho = m/V\) Solve this equation for the mass \(m\), then plug in the values for \(\varrho\), and \(V\)

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2NB ( 1 cm^3 = 1 ml )

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what does the NB stand for?

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2note well: \( 1\,[\text{cm}^3] = 1\,[\text{mL}]\))

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2OK, so you have (a), what do you think about (b)?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0would temperatures need to be added?

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2is temperature an extensive quantity, or intensive ?

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2right, so the temperature should become the average

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2what is the average of 17°C and 17°C ?

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2* is suppose it really should be the weighted average, but yes the temperatures are the same so the temperature wont change

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2which bits are unclear?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how I am suppose to use the average to figure out the final temperature

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2i don't think you are expected calculate the temperature, the temperatures are the same

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so it would be 17 as the final?

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2yeah, if you mix so water that is 17°C, with some more water that is 17°C, the temperature of the mixture will be 17°

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Alright. That makes sense now.

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2If they were different temperatures, then the final temperature would be some inbetween

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Gotcha. It makes sense now.

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2so what do you got for (c) ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You would multiple the final mass by the density to get volume.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So 160/160 = 1.00g/mL

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2(c) is asking for the final density, we know that density (like temperature, but unlike mass) is an intensive quality, i.e. density is a property of the material, rather than the object

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2the question states The density of water at 17°C is 1.00 [g/mL]. We found the final temperature of the mixture to be 17°C.

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2you don't have you multiply or divide to get (c),

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0why would we need to know the temperature for the final density?

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2because the density of water is temperature dependent

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay. Because of the intensive and extensive

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So you only have to look at it? Not do any math?

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2right , there is no math for (c), it is just: notice that our final temperature 17°C, is one at which we know the density to be 1 [g/mL]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what makes you realize that?

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2it's given in the question

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2we found the final temperature in (b), and the question tell us the density of water at this temperature

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2if the temperatures were different, and we calculated a weighted average temperature, we might use a table to look up the density of water at the temperature

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2We are combining objects with the same intensive properties, whereas, the extensive property (the mass) is the sum the intensive properties (temperature and density) of the mixture will be equal.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0because intensive is independent?

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2Yes, intensive properties are independent of the amount we have

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That makes sense now.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you again for the help.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.