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anonymous
 one year ago
Find the magnitude of
anonymous
 one year ago
Find the magnitude of

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ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.5magnitudes get divided when you divide two complex numbers : \[\left\dfrac{z_1}{z_2}\right = \dfrac{z_1}{z_2}\]

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.5so the magnitude of \(\large \eta^2 \) is given by : \[\large \eta^2 = \dfrac{\omega\mu}{\sqrt{\sigma^2+\omega^2\epsilon^2}}\]

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.5simply take the square root

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Why did you take off the square root at the numerator only?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and how did the denominator turn to that form?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.5the magnitude of numerator, \(j\omega \mu\), is just \(\omega \mu\) right

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.5its the same formula that you know magnitude of \(a+jb\) is given by \(\sqrt{a^2+b^2}\)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.5its just that mathematicians use \(i\) and physicists use \(j\) they both are same

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I need time to digest it. Thanks for explanation :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0One more question: They ask for magnitude of \(\eta\) , not \(\eta^2\), why did you turn it to \(\eta^2\)?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.5\(\eta = \sqrt{\eta^2}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0And after going around, you get back to \(\eta\), right? Thanks again. :)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.5Exactly, that wasn't supposed to be hard haha!

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.5technically the answer is simply \( \sqrt{\dfrac{\omega\mu}{\sqrt{\sigma^2+\omega^2\epsilon^2}}}\)
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