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anonymous

  • one year ago

[IMG] http://i62.tinypic.com/2nlqzvr.jpg [/IMG]

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  1. Koikkara
    • one year ago
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    @xfire30 Can you Please Re-draw the Picture in here ? To find current use Ohm's law. \(\Huge\tt\color{#CC0000}W\color{#CD0B00}e\color{#CF1700}l\color{#D12200}c\color{#D32E00}o\color{#D53900}m\color{#D74500}e~\color{#DB5C00}t\color{#DD6800}o~\color{#E17F00}O\color{#E38B00}p\color{#E59600}e\color{#E7A200}n\color{#E9AD00}S\color{#EBB900}t\color{#EDC500}u\color{#EFD000}d\color{#F1DC00}y\color{#F3E700}!\color{#F5F300}!\)

  2. mathmate
    • one year ago
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    Hints: Define the unknown currents i1,i2, i3. Use Kirchhoff's first law for the currents, and the second law for the voltages. (3 equations total) Solve for i1,i2 and i3. Post if you need further help.

  3. anonymous
    • one year ago
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    he's trying to embed the image like on http://goo.gl/YT4axB but it doesn't work here XD

  4. mathmate
    • one year ago
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    |dw:1441033342783:dw|

  5. mathmate
    • one year ago
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    Set up equations: at junction A: i3-i1-i2=0 ..............(1) Right loop: i3R3+i2R2=47............(2) Left loop : i1R1+i1Ri -i2R2 = 19 ................(3) Solve for the system of equations (1), (2) and (3) with three unknowns i1, i2 and i3. They all turn out to be positive integers, with i3 the maximum current (not a big surprise).

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