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Koikkara
 one year ago
Best ResponseYou've already chosen the best response.1@xfire30 Can you Please Redraw the Picture in here ? To find current use Ohm's law. \(\Huge\tt\color{#CC0000}W\color{#CD0B00}e\color{#CF1700}l\color{#D12200}c\color{#D32E00}o\color{#D53900}m\color{#D74500}e~\color{#DB5C00}t\color{#DD6800}o~\color{#E17F00}O\color{#E38B00}p\color{#E59600}e\color{#E7A200}n\color{#E9AD00}S\color{#EBB900}t\color{#EDC500}u\color{#EFD000}d\color{#F1DC00}y\color{#F3E700}!\color{#F5F300}!\)

mathmate
 one year ago
Best ResponseYou've already chosen the best response.0Hints: Define the unknown currents i1,i2, i3. Use Kirchhoff's first law for the currents, and the second law for the voltages. (3 equations total) Solve for i1,i2 and i3. Post if you need further help.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0he's trying to embed the image like on http://goo.gl/YT4axB but it doesn't work here XD

mathmate
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441033342783:dw

mathmate
 one year ago
Best ResponseYou've already chosen the best response.0Set up equations: at junction A: i3i1i2=0 ..............(1) Right loop: i3R3+i2R2=47............(2) Left loop : i1R1+i1Ri i2R2 = 19 ................(3) Solve for the system of equations (1), (2) and (3) with three unknowns i1, i2 and i3. They all turn out to be positive integers, with i3 the maximum current (not a big surprise).
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