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anonymous

  • one year ago

Match the reasons with the statements in the proof to prove that triangle ABC is congruent to triangle ABD, given that AB ⊥ BD, AB ⊥ BC, and AC = AD. Given: AB ⊥ BD AB ⊥ BC AC = AD Prove: △ABC ≅ △ABD

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  1. anonymous
    • one year ago
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    |dw:1440937731445:dw|

  2. anonymous
    • one year ago
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    1. AB ⊥ BD, AB ⊥ BC, AC = AD Given 2. ∠ABC and ∠ABD are right angles Hypotenuse - Leg Postulate 3. AB = AB Perpendicular Lines Form Right Angles 4. △ABC ≅ △ABD Reflexive Property of Equality

  3. sleepyhead314
    • one year ago
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    I was about to ask what you needed help with until I realized it was out of order xD :P the first line is correct ^_^ Given is just a repeat of the information they gave do you have to switch the order of the \(left~side\) at all, it seems like that is already in the same order :)

  4. sleepyhead314
    • one year ago
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    *in the correct order :P

  5. sleepyhead314
    • one year ago
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    2. <ABC and <ABD are right angles because "blah blah blah Form Right Angles" right? ;)

  6. sleepyhead314
    • one year ago
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    The Reflexive Property of Equality used with triangles is used when they are thinking about two different triangles (the ABC and ABD) and they share a same side like the "AB" of the ABC triangle, is the same "AB" of the ABD triangle therefore AB = AB

  7. sleepyhead314
    • one year ago
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    you should then have only one option left to match :) sorry for responding a little late to your question :3 [I just woke up] if you still are confused with any part of this question, feel free to tag me ^_^ @Sleepyhead314

  8. anonymous
    • one year ago
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    sorry i was logged on but wasnt on the page, i started to work on another problem because i thought nobody would help me. but thank you so much!!!! ^.^

  9. anonymous
    • one year ago
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    if i may, can i ask another question?

  10. anonymous
    • one year ago
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    @sleepyhead314

  11. anonymous
    • one year ago
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    In a word processing document or on a separate piece of paper, use the guide to construct a two column proof proving that triangle ADC is congruent to triangle CBA given that ∠D and ∠B are right angles and DC is parallel to AB. Submit the entire proof to your instructor. Given: ∠D and ∠B are right angles DC || AB Prove: △ADC ≅ △CBA

  12. anonymous
    • one year ago
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    |dw:1440940014259:dw|

  13. anonymous
    • one year ago
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    statement: reason: 1.∠D and ∠B are right angles 1. Given 2. 2. If lines are parallel, then alternate interior angles are equal 3. 3. 4. 4. Hypotenuse Angle Theorem

  14. sleepyhead314
    • one year ago
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    *nods off* mmm almost the same as beforeee you have right angles = right angles are congruent they share a side = reflexive property angle ACD and angle CAB are alternate interior angles then you'll have an AAS [angle angle side] postulate...

  15. sleepyhead314
    • one year ago
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    HA theroem? o-o google brb

  16. anonymous
    • one year ago
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    hypotunuse angle

  17. sleepyhead314
    • one year ago
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    gott it probably don't even need the reflexive part, but you can put it :P for the step 3 you got it last one would just be what they want to hear 4. triangle ACD is congruent to triangle CBA

  18. sleepyhead314
    • one year ago
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    oh wait, nope I take that back about reflexive you should use #3 to say that right angles are conguent

  19. anonymous
    • one year ago
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    so it will be statement: reason: △ADC ≅ △CBA right angles are congrent?

  20. anonymous
    • one year ago
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    like that?

  21. anonymous
    • one year ago
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    or am i wrong?

  22. sleepyhead314
    • one year ago
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    sorry for the confusion >,< the left side is right :) just make sure that's the last step and the reason should be the HA Theroem

  23. anonymous
    • one year ago
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    ahhh okay got it now, thank you so much for your help!! i have to loggoff now. thank thank you so much!!

  24. sleepyhead314
    • one year ago
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    glad I could help ^_^ have a nice day :P

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