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is your collision elastic?

or, how is defined the "coefficient of restitution"?

Oh well, the answer is \(\frac{1-e}{1+e}\)

That might help ....

no, sorry I'm not sure

It's ok, thnx for the effort though c:

let's suppose that our collision is perfectly inelastic, then we have this:
|dw:1440942312488:dw|

the two spheres are sticked together, after collision

on the other hand, if the collision is elastic, then we have this:
|dw:1440942582057:dw|

But in that case one of the final velocities will become 0, isn't it?

Yeah....

namely after collision the two spheres change their velocities

So basically, ratio will be 1:1 if the collision is inelastic...right?

And 0 if it's elastic?

the ratio is 1/2 if the collision is inelastic perfectly and 0 if that collision is elastic

So, the value of e must be in between 0-1

How, 1/2 , both the final velocities will be the same. Isn't it?

Umm..We need to find the ratio of velocities of both the ball after collision...

ok! then we have ratio=1

ok! :)

here is the article which I read:
https://en.wikipedia.org/wiki/Coefficient_of_restitution