freemap
  • freemap
A line is parallel to y = 1/3 x + 5 and passes through (–6, 0). A. y = –3x B. y = –3x + 2 C. y = 1/3 x + 2 D. y = 1/3 x – 6 Which is the equation of the line?
Mathematics
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SOLVED
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schrodinger
  • schrodinger
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madhu.mukherjee.946
  • madhu.mukherjee.946
option C
madhu.mukherjee.946
  • madhu.mukherjee.946
do i need to explain
freemap
  • freemap
Thanks, yes please

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More answers

madhu.mukherjee.946
  • madhu.mukherjee.946
okay
anonymous
  • anonymous
parallel means same slope
madhu.mukherjee.946
  • madhu.mukherjee.946
see two parallel lines have their slopes equal
dinamix
  • dinamix
its y=1/3(-6) +2 =0
freemap
  • freemap
I know, I thought you had to plug in again
madhu.mukherjee.946
  • madhu.mukherjee.946
the line you have has a slope of 1/3
madhu.mukherjee.946
  • madhu.mukherjee.946
so the required line will also have the same slope
madhu.mukherjee.946
  • madhu.mukherjee.946
do you get?
freemap
  • freemap
okay thanks so much
freemap
  • freemap
I do get it, computer lagging
madhu.mukherjee.946
  • madhu.mukherjee.946
now u use the formula y-y1=m(x-x1)
madhu.mukherjee.946
  • madhu.mukherjee.946
whenever you are asked to find a slope of a line wich passes through a point u will use this formula
madhu.mukherjee.946
  • madhu.mukherjee.946
now just plug in the values|dw:1440949360681:dw|
madhu.mukherjee.946
  • madhu.mukherjee.946
do you understand
freemap
  • freemap
I got it, thanks I know how to use the formula, its not different when doing perpendicular, from parraell Thanks understood
madhu.mukherjee.946
  • madhu.mukherjee.946
good:)
freemap
  • freemap
thanks again
madhu.mukherjee.946
  • madhu.mukherjee.946
your welcome

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