anonymous
  • anonymous
Can someone just help me solve this please?? i need an extraneous solution and it solved. i chose this but im not sure its correct. 2√x+5+7=4
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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stefrheart
  • stefrheart
Is that the original equation?
anonymous
  • anonymous
no it said to choose your own using a√x+b+c=d
stefrheart
  • stefrheart
Ah I understand hold for a minute please

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anonymous
  • anonymous
okay.
stefrheart
  • stefrheart
I dont think it has an extraneous solution because I got x=16
anonymous
  • anonymous
well could you help me find one with one please? using the a√x+b+c=d formula thingy
stefrheart
  • stefrheart
Sure!
stefrheart
  • stefrheart
So you do understand what an extraneous solution is correct?
anonymous
  • anonymous
i think it is how it solves the problem but if you plug it back in it doesnt work out
anonymous
  • anonymous
like if you solve the radical but if you plug it in to check the answer will not work out
stefrheart
  • stefrheart
Yes that is correct! :)
anonymous
  • anonymous
im not sure how to like create and solve a radical like that though... ;(
anonymous
  • anonymous
Create two radical equations: one that has an extraneous solution, and one that does not have an extraneous solution. Use the equation below as a model. a√x+b+c=d Use a constant in place of each variable a, b, c, and d. You can use positive and negative constants in your equation.
stefrheart
  • stefrheart
is it \[a \sqrt{x+b+c}=d\] or \[a \sqrt{x} + b + c=d\]
phi
  • phi
try something like \[ \sqrt{x+2} + 1 = -1 \]
anonymous
  • anonymous
the first one @stefrheart
anonymous
  • anonymous
@phi the only problem is is that i don't know how to solve that equation to check if it has an extraneous solution
stefrheart
  • stefrheart
To solve that all you need to do is subtract the one on both sides to create \[\sqrt{x+2}=-2\] and then square both sides \[(\sqrt{x+2})^{2}=(-2)^{}\] and then solve
stefrheart
  • stefrheart
just for phi's equation
dinamix
  • dinamix
x=-8 @stefrheart
dinamix
  • dinamix
@kenzi041
anonymous
  • anonymous
i dont even know. i never learned radicals
stefrheart
  • stefrheart
oh you dont know what a radical is or how to work with it?
anonymous
  • anonymous
we had a large learning gap because they changed curriculums
anonymous
  • anonymous
not really.
stefrheart
  • stefrheart
Ah okay so you should learn what a radical is first then, before proceeding with the problem
anonymous
  • anonymous
oh.
stefrheart
  • stefrheart
It would make alot more sense before solving this. Do you know what a \[x ^{2}\] is? It would be easier to teach you if you knew what it is
anonymous
  • anonymous
x squared?
stefrheart
  • stefrheart
yes you know what to do with it if someone gave you the equation \[4^{2}\] ?
anonymous
  • anonymous
16, i know like how to do that i just dont understand how to use like larger equations like a√x+b+c=d
stefrheart
  • stefrheart
Ah okay so you know how to do that. Well the larger equations are just the same ting as a regular square root.
anonymous
  • anonymous
okay, so how do i find one with an extraneous solution
anonymous
  • anonymous
because i have one for without but i just need one with one
stefrheart
  • stefrheart
I think I may have one hold on
anonymous
  • anonymous
ok
dinamix
  • dinamix
x=-8 u have check in the equation ans see it
stefrheart
  • stefrheart
Whats the extraneous solution then? @dinamix
anonymous
  • anonymous
like how do you plug it in to check if it has one @dinamix
stefrheart
  • stefrheart
Try this for help https://www.khanacademy.org/math/algebra2/radical-equations-and-functions/radical-equations/e/extraneous-solutions-to-radical-equations
anonymous
  • anonymous
i already tried but it was in a different format than what the question asked
stefrheart
  • stefrheart
Yeah I noticed ​​
anonymous
  • anonymous
and i got more confused..
stefrheart
  • stefrheart
Hmmm im trying to figure out equations because in order for it to have both an actual and extraneous there needs to be 2 solutions which is a \[x ^{2}+bx+c\] unless we can do that you cant get both an actual and extraneous
anonymous
  • anonymous
no it needs to just be a extraneous solution.. you write two problems and one should be regular and one should have an extraneous solution
stefrheart
  • stefrheart
Ohhh then I already have one then
stefrheart
  • stefrheart
\[-5\sqrt{-3x-5}=-25\]
anonymous
  • anonymous
but doesnt it have to be x+b+c=d
stefrheart
  • stefrheart
if you wwant it you can just put -3x+-5+0 for under the radical
anonymous
  • anonymous
okay, one sec im checking a problem i just did.
stefrheart
  • stefrheart
I will be back in a few minutes
anonymous
  • anonymous
i think i found one, the problem i chose originally
anonymous
  • anonymous
and okay
stefrheart
  • stefrheart
AH okay
stefrheart
  • stefrheart
Message me if need you still need help
anonymous
  • anonymous
thanks for helping
anonymous
  • anonymous
how do i give u a medal?
stefrheart
  • stefrheart
@kenzi041 click the best response
anonymous
  • anonymous
@stefrheart i failed, but thanks anyway
stefrheart
  • stefrheart
Aw im sorry :( @kenzi041

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