## anonymous one year ago Can someone just help me solve this please?? i need an extraneous solution and it solved. i chose this but im not sure its correct. 2√x+5+7=4

1. stefrheart

Is that the original equation?

2. anonymous

no it said to choose your own using a√x+b+c=d

3. stefrheart

Ah I understand hold for a minute please

4. anonymous

okay.

5. stefrheart

I dont think it has an extraneous solution because I got x=16

6. anonymous

well could you help me find one with one please? using the a√x+b+c=d formula thingy

7. stefrheart

Sure!

8. stefrheart

So you do understand what an extraneous solution is correct?

9. anonymous

i think it is how it solves the problem but if you plug it back in it doesnt work out

10. anonymous

like if you solve the radical but if you plug it in to check the answer will not work out

11. stefrheart

Yes that is correct! :)

12. anonymous

im not sure how to like create and solve a radical like that though... ;(

13. anonymous

Create two radical equations: one that has an extraneous solution, and one that does not have an extraneous solution. Use the equation below as a model. a√x+b+c=d Use a constant in place of each variable a, b, c, and d. You can use positive and negative constants in your equation.

14. stefrheart

is it $a \sqrt{x+b+c}=d$ or $a \sqrt{x} + b + c=d$

15. phi

try something like $\sqrt{x+2} + 1 = -1$

16. anonymous

the first one @stefrheart

17. anonymous

@phi the only problem is is that i don't know how to solve that equation to check if it has an extraneous solution

18. stefrheart

To solve that all you need to do is subtract the one on both sides to create $\sqrt{x+2}=-2$ and then square both sides $(\sqrt{x+2})^{2}=(-2)^{}$ and then solve

19. stefrheart

just for phi's equation

20. dinamix

x=-8 @stefrheart

21. dinamix

@kenzi041

22. anonymous

i dont even know. i never learned radicals

23. stefrheart

oh you dont know what a radical is or how to work with it?

24. anonymous

we had a large learning gap because they changed curriculums

25. anonymous

not really.

26. stefrheart

Ah okay so you should learn what a radical is first then, before proceeding with the problem

27. anonymous

oh.

28. stefrheart

It would make alot more sense before solving this. Do you know what a $x ^{2}$ is? It would be easier to teach you if you knew what it is

29. anonymous

x squared?

30. stefrheart

yes you know what to do with it if someone gave you the equation $4^{2}$ ?

31. anonymous

16, i know like how to do that i just dont understand how to use like larger equations like a√x+b+c=d

32. stefrheart

Ah okay so you know how to do that. Well the larger equations are just the same ting as a regular square root.

33. anonymous

okay, so how do i find one with an extraneous solution

34. anonymous

because i have one for without but i just need one with one

35. stefrheart

I think I may have one hold on

36. anonymous

ok

37. dinamix

x=-8 u have check in the equation ans see it

38. stefrheart

Whats the extraneous solution then? @dinamix

39. anonymous

like how do you plug it in to check if it has one @dinamix

40. stefrheart
41. anonymous

i already tried but it was in a different format than what the question asked

42. stefrheart

Yeah I noticed ​​

43. anonymous

and i got more confused..

44. stefrheart

Hmmm im trying to figure out equations because in order for it to have both an actual and extraneous there needs to be 2 solutions which is a $x ^{2}+bx+c$ unless we can do that you cant get both an actual and extraneous

45. anonymous

no it needs to just be a extraneous solution.. you write two problems and one should be regular and one should have an extraneous solution

46. stefrheart

Ohhh then I already have one then

47. stefrheart

$-5\sqrt{-3x-5}=-25$

48. anonymous

but doesnt it have to be x+b+c=d

49. stefrheart

if you wwant it you can just put -3x+-5+0 for under the radical

50. anonymous

okay, one sec im checking a problem i just did.

51. stefrheart

I will be back in a few minutes

52. anonymous

i think i found one, the problem i chose originally

53. anonymous

and okay

54. stefrheart

AH okay

55. stefrheart

Message me if need you still need help

56. anonymous

thanks for helping

57. anonymous

how do i give u a medal?

58. stefrheart

@kenzi041 click the best response

59. anonymous

@stefrheart i failed, but thanks anyway

60. stefrheart

Aw im sorry :( @kenzi041