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anonymous
 one year ago
How to integrate the following:
2x/(x^31)
anonymous
 one year ago
How to integrate the following: 2x/(x^31)

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[I=\int\limits \frac{2 x }{\left( x1 \right)\left( x^2+x+1 \right) }dx\] \[\frac{ 2x }{\left( x1 \right)\left( x^2+x+1 \right) }=\frac{ A }{ x1 }+\frac{ Bx+C }{ x^2+x+1 }\] \[2x=A \left( x^2+x+1 \right)+\left( Bx+C \right)\left( x1 \right)\] equate terms like powers of x 0=A+B 2=AB+C 0=AC find A,B,C and integrate.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can you complete it?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0http://prntscr.com/8an7mo this term is much complicated

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thanks Surjithayer. Your reply was very helpful and I could complete it.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Unable to get correct Answer. Can you further solve To final answer.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0A+B=0,B=A AC=0 C=A 2=A+A+A \[A=\frac{ 2 }{ 3 },B=A=\frac{ 2 }{ 3 },C=A=\frac{ 2 }{ 3 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[I=\int\limits \frac{ \frac{ 2 }{ 3 } }{ x1 }dx+\int\limits \frac{ \frac{ 2 }{ 3 }x+\frac{ 2 }{ 3 } }{ x^2+x+1 }dx\] \[=\frac{ 2 }{ 3 }\ln \left( x1 \right)\frac{ 1 }{ 3 }\int\limits \frac{ 2x2 }{ x^2+x+1 }dx\] \[=\frac{ 2 }{ 3 }\ln \left( x1 \right)\frac{ 1 }{ 3 }\int\limits \frac{ 2x+13 }{ x^2+x+1 }dx\] \[=\frac{ 2 }{ 3 }\ln \left( x1 \right)\frac{ 1 }{ 3 }\int\limits \frac{ 2x+1 }{ x^2+x+1 }dx+\int\limits \frac{ 1 }{x^2+x+1 }dx\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thanks Surjithayer now it is clear.
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