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freemap

  • one year ago

The table shows the approximate population of a city, in thousands, for the years 2009–2013. Which is the best prediction for the city’s approximate population in 2030? A. 153,000 B. 167,000 C. 182,000 D. 195,000

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  1. freemap
    • one year ago
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  2. Vocaloid
    • one year ago
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    well, I would treat years as the x variable and population as the y variable, then write an equation using two points from the table I'll pick the first and last point (2009,78) and (2013,93) then write an equation in y = mx + b form

  3. freemap
    • one year ago
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    OK, about to it work out

  4. freemap
    • one year ago
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    I got 1920 and -1936 and when I didvided got -1.00833so on. I don't think I did it right

  5. Vocaloid
    • one year ago
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    remember, slope = (y2-y1)/(x2-x1) (93-78) = ?

  6. freemap
    • one year ago
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    I was doing 93-73 okay I'm about to do it all over

  7. freemap
    • one year ago
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    I mean I was doing 93 minus 2013 okay about to work it all out again

  8. freemap
    • one year ago
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    okay I got 3.75 for slope, than I have to work out to get y intercept

  9. freemap
    • one year ago
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    ok my slope is 3.75, then I said y-y1=m(x-x1) so it was y-78=3.75-2009 which i got + 78 to -2009= 1931

  10. freemap
    • one year ago
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    I'm kinda lost now

  11. freemap
    • one year ago
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    wait I think I figured it out and got 2029

  12. Vocaloid
    • one year ago
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    ah, I think you've mixed up the equation a bit, let me lend you a hand ^ ^ y-78 = 3.75(x-2009) start by distributing the 3.75

  13. freemap
    • one year ago
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    y-78=3.75x-7533.75 y-78+78=3.75x +78-7533.75 y=3.75x-7455.75 3.75x/-7455.75

  14. Vocaloid
    • one year ago
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    you can stop here y=3.75x-7455.75 this is the equation we need, now plug in x = 2030

  15. freemap
    • one year ago
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    ok so 3.75 times 2030. if so that =7612.5

  16. Vocaloid
    • one year ago
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    uh, not quite... we're looking for the value of y 3.75*(2030) - 7455.75

  17. Vocaloid
    • one year ago
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    = ?

  18. freemap
    • one year ago
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    2030-7455.75

  19. freemap
    • one year ago
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    I meant 7612.5-7455.75

  20. Vocaloid
    • one year ago
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    ok, now subtract those two values

  21. freemap
    • one year ago
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    156.75

  22. Vocaloid
    • one year ago
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    good, now we multiply by 1000 to get 156,750 which means that A is the answer that best approximates the population in 2030

  23. freemap
    • one year ago
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    Thanks, I don't know to say. You've always been there to help me. Thanks

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