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anonymous

  • one year ago

x(t) = 5 + 3t - 4t^2 = 5t^3 find the derivative

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  1. Luigi0210
    • one year ago
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    Is that "=" suppose to be a "+"?

  2. anonymous
    • one year ago
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    Yes , sorry. its suppose to be x(t)= 5 + 3t - 4t^2 + 5t^3

  3. triciaal
    • one year ago
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    @bryeshia4 is there a special reason why the polynomial is written backwards?

  4. anonymous
    • one year ago
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    @triciaal can u help on my question I mentioned u in?

  5. triciaal
    • one year ago
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    |dw:1440955362494:dw|

  6. anonymous
    • one year ago
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    @triciaal No!

  7. triciaal
    • one year ago
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    |dw:1440955482475:dw|

  8. idku
    • one year ago
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    basically, that: \(x(t)=5+3t-4t^2+5t^3\) for the derivative of a constant, you get 0, and for the rest terms you apply the power rule to - each time: Power rule: \(\color{royalblue}{d/dt~~(t^n)~=~(n)\cdot t^{n-1}}\) \(x\color{red}{`}(t)={\color{red}{0}}+(1)3t^{1\color{red}{-1}}-(2)4t^{2\color{red}{-1}}+(3)5t^{3\color{red}{-1}}\)

  9. idku
    • one year ago
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    x'(t) is a notation for the derivative of the function x(t)

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