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anonymous
 one year ago
x(t) = 5 + 3t  4t^2 = 5t^3
find the derivative
anonymous
 one year ago
x(t) = 5 + 3t  4t^2 = 5t^3 find the derivative

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Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.0Is that "=" suppose to be a "+"?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes , sorry. its suppose to be x(t)= 5 + 3t  4t^2 + 5t^3

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0@bryeshia4 is there a special reason why the polynomial is written backwards?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@triciaal can u help on my question I mentioned u in?

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1440955362494:dw

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1440955482475:dw

idku
 one year ago
Best ResponseYou've already chosen the best response.0basically, that: \(x(t)=5+3t4t^2+5t^3\) for the derivative of a constant, you get 0, and for the rest terms you apply the power rule to  each time: Power rule: \(\color{royalblue}{d/dt~~(t^n)~=~(n)\cdot t^{n1}}\) \(x\color{red}{`}(t)={\color{red}{0}}+(1)3t^{1\color{red}{1}}(2)4t^{2\color{red}{1}}+(3)5t^{3\color{red}{1}}\)

idku
 one year ago
Best ResponseYou've already chosen the best response.0x'(t) is a notation for the derivative of the function x(t)
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