anonymous one year ago A football quarterback has 2 more chances to throw a touchdown before his team is forced to punt the ball. He misses the receiver on the first throw 30% of the time. When his first throw is incomplete, he misses the receiver on the second throw 10% of the time. What is the probability of not throwing the ball to a receiver on either throw?

1. anonymous

$P_{\text{miss1, miss2}} = P_{\text{miss1}} \times P_{\text{miss2}}$

2. anonymous

what

3. anonymous

so it would be 300?

4. anonymous

@ospreytriple

5. anonymous

You must convert the percentages to decimals before multiplying them together.

6. anonymous

so, 3%

7. anonymous

Correct. Good job.