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anonymous
 one year ago
Draw a 105 degree angle
anonymous
 one year ago
Draw a 105 degree angle

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mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2dw:1440958077956:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it says using a ruler and a protractor @mathstudent55

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0Just follow this video. https://www.youtube.com/watch?v=t4xCOUNEInI

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2I only see "Draw a 105 degree angle" above.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0would you like me to re write the question ? @mathstudent55

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2Here's my way of doing it.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2Start with a line, and mark two points on the line. dw:1440958648016:dw

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2We are going to draw a square segment AB as a side. dw:1440958758007:dw

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2Open the compass to AB and center it at A and draw an arc. Using the same opening, center it at B and draw an arc. dw:1440958818783:dw

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2Now we want to draw a perpendicular to line AB through point A and a perpendicular to line AB through point B. Open the compass to any opening between AB. Center the compass at A and draw and two arcs on line AB, one on each side of A. dw:1440959091893:dw

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2dw:1440959116221:dw

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2Now open the compass more than AD, center is at C and center it at D and draw two arcs above A.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2dw:1440959214600:dw

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2Connect A to E and extend. dw:1440959255726:dw

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2FE is perpendicular to AB. Also, FA = AB

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2Now open the compass to AB. Center the compass at F and draw and arc to intersect the arc above B. dw:1440959563117:dw

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2G is the 4th vertex of our square.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2We have square ABGF. Since it's a square, all vertex angles are 90 degrees. dw:1440959604880:dw

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2dw:1440959655179:dw

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2Now we extend line BG up above point G. dw:1440959701330:dw

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2Now we need half the length of the segment BG, so we draw its perpendicular bisector. Open the compass to more than half of BG. Center the compass at G and draw two arcs. Then center the compass at B and draw two arcs that intersect the previous two arcs. Connect the intersections of the arcs with a segment. This segment is the perpendicular bisector of segment BG. dw:1440959917480:dw

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2GH is half of BG.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2Open the compass to GH. Center the compass at G and mark a point above G on line BG. dw:1440960034307:dw

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2Sorry. I realize now I made a mistake when I tried to figure this out earlier. We don't need half the side.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2Let's go back to the square.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2dw:1440960509048:dw

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2Now we draw a diagonal in the square.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2Since we constructed a square, we know each vertex angle measures 90 degrees. Also, when we draw a diagonal, that bisects the vertex angle, so we have now two 45 degree angles at the vertex. dw:1440960561813:dw

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2We notice that 105 degrees = 45 degrees + 60 degrees. If we place a 60 degree angle at that vertex, then 60 deg + 45 deg = 105 deg, which is what we want.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2A 60deg angle is not difficult to construct because it is the measure of the vertex angles of an equilateral triangle.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2Now we construct an equilteral triangle at the upper left vertex of the square.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2dw:1440960839669:dw

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2Open the compass to AB and center at F. Draw and arc. Then center at G and draw an arc. Where the arcs intersect, it's the third vertex of equilateral triangle FGP. dw:1440960981941:dw

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2dw:1440961010150:dw

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2Angle PFG measures 60 deg. Angle GFB measures 45 deg. Angle PFB measures 105 deg.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2With the help of a square, its diagonal, and an equilateral triangle, we now have a 105deg angle.
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