2nd integer question

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2nd integer question

Mathematics
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It says that the integers are consecutive, so each integer must be 1 more than the integer before it. So, the table will look exactly like the one in the previous question. OK?

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Other answers:

In this question, you need to add the 2nd and 3rd integers. What do you get?
x+1 then x+3
Sorry, I messed up. It says that the integers are consecutive EVEN integers. So if the first EVEN integer is x, what is the next EVEN integer?
x+1?
Not quite. For example, if the first even integer is 4, what is the next even integer?
x+5
Whoa. Let's back up. What is the next largest even integer after 4?
5?
Do you know what an even number is?
It's OK. Yes or no?
The next even number after 4 is 6
Correct. So, if you have any even integer, how much to you have to add to it to get the next largest even integer?
the next even number from x would be 2 correct?
No. If x is an even integer, how much do you have to add to it to get the next largest even integer?
It seems you recognize that even integers are two numbers apart. So the next largest even integer to an even integer x is 2 more than x. How do you write "2 more than x" mathematically?
Hello? Do you still help?
*need help?
I'm sorry I'm just really stressed out on this assignment, I've been doing it for over 3 hours.
OK. Stay with me and we'll work it out together. Can you answer my last question?
2+x
Right! Except we would normally write it as x + 2. What is the next even integer after x + 2 ?
x+4
Excellent. Now your table is filled out. First even integer: x Next even integer: x + 2 Next even integer: x + 4 The question asks for the sum of the second and third ones. Can you do that?
Yes.
What do you get?
I think I did it wrong. I got 6.
\[\left( x+2 \right) + \left( x+4 \right) = ?\]
2x+6
Correct. Good job!

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