2nd integer question

- anonymous

2nd integer question

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- anonymous

Go ahead

- anonymous

##### 1 Attachment

- anonymous

It says that the integers are consecutive, so each integer must be 1 more than the integer before it. So, the table will look exactly like the one in the previous question. OK?

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## More answers

- anonymous

In this question, you need to add the 2nd and 3rd integers. What do you get?

- anonymous

x+1 then x+3

- anonymous

Sorry, I messed up. It says that the integers are consecutive EVEN integers. So if the first EVEN integer is x, what is the next EVEN integer?

- anonymous

x+1?

- anonymous

Not quite. For example, if the first even integer is 4, what is the next even integer?

- anonymous

x+5

- anonymous

Whoa. Let's back up. What is the next largest even integer after 4?

- anonymous

5?

- anonymous

Do you know what an even number is?

- anonymous

It's OK. Yes or no?

- anonymous

The next even number after 4 is 6

- anonymous

Correct. So, if you have any even integer, how much to you have to add to it to get the next largest even integer?

- anonymous

the next even number from x would be 2 correct?

- anonymous

No. If x is an even integer, how much do you have to add to it to get the next largest even integer?

- anonymous

It seems you recognize that even integers are two numbers apart. So the next largest even integer to an even integer x is 2 more than x. How do you write "2 more than x" mathematically?

- anonymous

Hello? Do you still help?

- anonymous

*need help?

- anonymous

I'm sorry I'm just really stressed out on this assignment, I've been doing it for over 3 hours.

- anonymous

OK. Stay with me and we'll work it out together. Can you answer my last question?

- anonymous

2+x

- anonymous

Right! Except we would normally write it as x + 2. What is the next even integer after x + 2 ?

- anonymous

x+4

- anonymous

Excellent. Now your table is filled out.
First even integer: x
Next even integer: x + 2
Next even integer: x + 4
The question asks for the sum of the second and third ones. Can you do that?

- anonymous

Yes.

- anonymous

What do you get?

- anonymous

I think I did it wrong. I got 6.

- anonymous

\[\left( x+2 \right) + \left( x+4 \right) = ?\]

- anonymous

2x+6

- anonymous

Correct. Good job!

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