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anonymous

  • one year ago

I don't understand implicit differentiation at all. Anyone willing to help?

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  1. anonymous
    • one year ago
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    @peachpi i need ur help

  2. Empty
    • one year ago
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    Yeah I can help you with implicit differentiation, what would you like to know? If you have some problem we could work through or if you want me to make one up it might help.

  3. Castiel
    • one year ago
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    I'm actually studying that too now so I'll try to help as well

  4. Loser66
    • one year ago
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    Thanks for reply. " I " am offline now. hwahahaha....

  5. anonymous
    • one year ago
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    @Empty If you could make up a problem and do a step-by-step review that would help a lot. Thank you

  6. Empty
    • one year ago
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    Sure, let's look at this problem and just do implicit differentiation. \[y^{1/2}=x\] doing implicit differentiation (for no real reason, we could just square both sides and to this normally, but let's pretend we didn't notice that) we get: \[\frac{1}{2} y^{-1/2}y' = 1\] Let's solve for y', \[y' = 2y^{1/2}\] Plug in the original value from the start for \(y^{1/2}=x\) to get \[y'=2x\] which is totally what we would have gotten had we done it the simpler way.

  7. anonymous
    • one year ago
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    Okie Doke. Thank you so much @Empty

  8. Empty
    • one year ago
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    That's it? No questions? :?

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