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anonymous
 one year ago
Re: 6.00 Handout, Lecture 2
http://tinyurl.com/q35p8dy
The handout has the following code:
''''
if x < y:
if x < z:
print 'x is least'
else:
print 'z is least'
else:
print 'y is least'
'''
why is else: y is least
?
if x = 3
y = 2
z = 1
z is the least
anonymous
 one year ago
Re: 6.00 Handout, Lecture 2 http://tinyurl.com/q35p8dy The handout has the following code: '''' if x < y: if x < z: print 'x is least' else: print 'z is least' else: print 'y is least' ''' why is else: y is least ? if x = 3 y = 2 z = 1 z is the least

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Write after the code I post, is the following: ''' if x < y: if x < z: print 'x is least' else: print 'z is least' elif y < z: print 'y is least' ''' Which does make sense and later in the code it addresses if z is the least.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0To clarify, the difference between the command in the 1st post and 2nd post is ese vs. elif respectively.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The handout has the correct code boxed in a rectangle
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