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anonymous

  • one year ago

Can some one please help me step by step to solve these two problems? Screen shots included. Medal!

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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    I'm not sure... I may get the question wrong. You should probably use this formula A=1/2 BH

  3. anonymous
    • one year ago
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    This is my first time doing this I need like a step by step on how to do it

  4. anonymous
    • one year ago
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    Hmm, I'm sorry.. I dont get it either lol really wish I did.. but it's confusing

  5. calculusxy
    • one year ago
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    Use the Pythagorean Theorem \[a^2 + b^2 = c^2 \]

  6. welshfella
    • one year ago
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    use pythagorss theorem

  7. calculusxy
    • one year ago
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    For question 1 we know that a = 16 and b = 63 so let's plug that into the formula to find c (hypotenuse) \[16^2 + 63^2 = c^2 \]

  8. anonymous
    • one year ago
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    16^2 + 63^ =c^2 lol

  9. calculusxy
    • one year ago
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    Do you understand how to find the answer to this problem?

  10. anonymous
    • one year ago
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    4,225?

  11. calculusxy
    • one year ago
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    Good and then find the aquaria root of 4,225 because when c is being squared, it equals to 4225.

  12. calculusxy
    • one year ago
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    *square root

  13. anonymous
    • one year ago
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    65

  14. calculusxy
    • one year ago
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    correct!

  15. anonymous
    • one year ago
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    Thank you can you wait until I do the second problem so i can see if its right?

  16. calculusxy
    • one year ago
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    Sure !

  17. anonymous
    • one year ago
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    would the answer be 3.5805.?

  18. calculusxy
    • one year ago
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    Let's check! \[a^2 + 2.1^2 = 2.9^2\] \[a^2 = 4\] (because 2.9^2 - 2.1^2) \[a = \sqrt4\]

  19. anonymous
    • one year ago
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    ohhh okay! I just plugged it in wrong

  20. anonymous
    • one year ago
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    Thank you! I'll contact you if i need help with anything else

  21. calculusxy
    • one year ago
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    Sure! and You're welcome :)

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